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∙ 13y agoThis quantity is equivalent to 90 g glucose / kg water = 0.50 mole particles of solute / kg water, so with a 'molar cryoscopic constant' for water of -1.86 oC/kgthis lowers the freezing point to -0.93 oC.
Wiki User
∙ 13y agoThe boiling point of water increases by 0.51 degrees Celsius, and the freezing point decreases by 1.86 degrees Celsius for a 1-molal solution of glucose in water. Since we have a 45-gram portion of glucose in 500 grams of water, we can calculate the molality and use it to determine the changes in the boiling and freezing points.
The chemical formula for glucose dissolving in water is: C6H12O6 +6O2 ---->6CO2 +6H2O.
Glucose is a simple sugar with the chemical formula C6H12O6. It is a monosaccharide and a key source of energy for living organisms.
The boiling point of a solution can vary depending on the concentration of solute. For a dilute solution of glucose in water, the boiling point elevation is typically small and may not be easily measurable. However, pure glucose itself does not have a defined boiling point as it decomposes upon heating.
C6H12O6. 6 atoms of carbon, 12 atoms of hydrogen, 6 atoms of oxygen.
C6H12O6 is the chemical formula for glucose, a simple sugar that is an essential source of energy for living organisms.
The chemical formula for glucose dissolving in water is: C6H12O6 +6O2 ---->6CO2 +6H2O.
The chemical formula for glucose is C6H12O6.
The boiling point of a solution can vary depending on the concentration of solute. For a dilute solution of glucose in water, the boiling point elevation is typically small and may not be easily measurable. However, pure glucose itself does not have a defined boiling point as it decomposes upon heating.
To find the molarity of the solution, we need to first calculate the number of moles of glucose in 154 grams. The molar mass of glucose is 180 g/mol. Dividing 154 g by 180 g/mol gives us 0.856 moles of glucose. Since the volume is 1 liter, the molarity is 0.856 M.
A 1M solution of glucose will have higher boiling and freezing points compared to a 1M solution of CaCl2. This is because CaCl2 dissociates into three ions (1 Ca2+ and 2 Cl-) per formula unit in solution, leading to a higher boiling point due to increased colligative properties. Additionally, the presence of more solute particles hinders the formation of a solid lattice structure, resulting in a lower freezing point.
The normal sugar is Sucrose, when it is dissolved in water it slowly decomposes to Glucose and Fructose. The reaction is catalised by acids (H+) like present in softdrinks.C12H22O11 + H2O --[H+]--> C6H12O6(Glucose) + C6H12O6(Fructose)
The formula for glucose is C6H12O6, and the formula for fructose is C6H12O6. They both have the same chemical formula but different structures, as they are isomers of each other.
The chemical compound for glucose is C6H12O6, representing its molecular formula.
The chemical formula for glucose is C6H12O6.
The symbol used to represent glucose is C6H12O6.
C6H12O6
C6H12O6.