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Determine the bond order in a molecule or ion with 14 valance electrons

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Ashlee Yancey

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3y ago
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AnswerBot

5mo ago

The bond order of an ion with 8 valence electrons would depend on the specific atom and its bonding situation. For example, an oxygen atom typically forms two bonds, resulting in a bond order of 2. However, if the atom has gained or lost electrons to form an ion, the bond order can change accordingly.

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Wiki User

11y ago

"It is impossible to have 13 valence electrons, the maximum you can have is 8 so your question is not possible"

^^^

This guy is a coms major. The answer is 1.5

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Wiki User

15y ago

it is diamagnetic

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13y ago

bond order: 2

paramagnetic

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Wiki User

11y ago

Bond Order: 1

Diamagnetic

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14y ago

Zero, for noble gases (group 18)

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11y ago

3

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Q: What is the bond order of an ion with 8 valence electrons?
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What is happening to valence electrons in a purely ionic bond?

In the atom which will form the positive ion, the valence electrons is/are being given up and lost to the reaction medium (environment). In the atom which will form the negative ion, the valence electrons lingering in the reaction medium will be attracted to the proton of the negative ion and is taken in by the negative ion.


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The lithium ion will be stripped of its electron by the flouride ion, resulting in an ionic bond, where the lithium atom will have 0 valence electrons and the fluoride ion will have 8


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The lithium ion will be stripped of its electron by the flouride ion, resulting in an ionic bond, where the lithium atom will have 0 valence electrons and the fluoride ion will have 8


Is the oxidation number of an ion equal to the number of valence electrons the ion contains?

Yes, the oxidation number of an ion is equal to the number of valence electrons the ion contains. Valence electrons are the electrons in the outermost shell of an atom, and they are involved in forming chemical bonds, which also determines the oxidation state of an ion.


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How many valence electrons are in a chlorine atom and a chloride ion?

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