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If you mean the balanced reaction of the combustion of propane, it is:
C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
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∙ 12y ago
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Is it likely that the equation C3H8 plus 5 02 - 3 CO2 plus 4 H2O represents the reaction mechanism for the cumbustion of propane?
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 → 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
When propane burns in oxygen it forms carbon dioxide and water write the balanced equation?
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
What is the equation of the combustion of propane?
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
5
Can C3H8 5O2 3CO2 4H2O be a combustion reaction?
Yes, the reaction C3H8 + 5O2 -> 3CO2 + 4H2O is a combustion reaction. Combustion reactions involve a fuel (in this case, propane - C3H8) reacting with oxygen to produce carbon dioxide and water.
How does a balanced equation for the burning of propane look like?
The balanced equation for the burning of propane (C3H8) is: C3H8 + 5O2 -> 3CO2 + 4H2O
What is the balanced equation of the monobromination of propane?
The balanced equation for the monobromination of propane is C3H8 + Br2 -> C3H7Br + HBr.
What is c3h8 o2--co2 h2o balanced?
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
What is balanced equation for the burning of propane?
C3H8 + 5O2 --> 3CO2 + 4H2O
When propane gas is burned with oxygen the products are carbon dioxide and water write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
When propane gas is burned with oxygen the products are carbon dioxide and water. write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
what is this answer C3H8 + 5O2 3CO2 + 4H2O?
This answer represents a balanced chemical equation for the combustion of propane (C3H8). When propane reacts with oxygen (O2), it produces carbon dioxide (CO2) and water (H2O).
How many moles of oxygen are necessary to react completely with 4 moles of propane?
For the reaction of propane (C3H8) with oxygen (O2), the balanced equation is: C3H8 + 5O2 -> 3CO2 + 4H2O. This means that 5 moles of O2 are required to react completely with 1 mole of propane (C3H8). Therefore, to react completely with 4 moles of propane, you would need 20 moles of O2.
What is the balanced equation of the combustion of propane to produce carbon dioxide and water vapor?
The balanced chemical equation for the combustion of propane (C3H8) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This equation shows that when one molecule of propane reacts with five molecules of oxygen, it produces three molecules of carbon dioxide and four molecules of water.
When propane burns in oxygen it forms carbon dioxide and water write the balanced equation?
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
What is the equation of the combustion of propane?
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
Chemical formula for propane?
Propane ( C3H8 ) will burn completely when it combines with the oxygen (O2) in air to form carbon dioxide (CO2) and water (H2O). The equation looks like this: C3H8 + 5O2 ---> 3CO2 + 4H2O The heat generated in the exothermic reaction causes more and more propane to "break apart" and combine with oxygen in air to produce the end products carbon dioxide and water. This will continue until the concentration of propane in air falls below a "threshold" and not enough heat is generated to support the combustion of any remaining propane. There is enough oxygen in air in an open space to support the combustion of an extremely large volume of propane.
