The equation is:
CaCO3.......................→CaO + CO2
Chat with our AI personalities
The coefficient for carbon dioxide in the balanced equation C5H12I + 8 O2 -> 5 CO2 + 6 H2O is 5.
Decomposition reaction: CaCO3(s) --(heat)--> CaOs + CO2(g)
The balanced chemical equation is: CO2(g) + 2KOH(s) -> H2O(g) + K2CO3(s). The enthalpy change (ΔHrxn) for this reaction is the enthalpy of formation of the products minus the enthalpy of formation of the reactants. To calculate it, you would need the standard enthalpies of formation for all species involved.
Co2 is a compound (or a composite i don't know exactly) and as you know all the compounds are homogeneous and pure.
Keq = [H2O][CO] [H2][CO2]
The redox reaction can be identified by the transfer of electrons. In this case, the correct redox equation is: 2Ag(s) + 2NO3^-(aq) + 2BaCl2(aq) + Na2CrO4(aq) + 3H3PO4(aq) + 6KOH(aq) + 3CaCO3(s) -> 2Ag^+(aq) + 2NO3^-(aq) + Cu(NO3)2(aq) + BaCrO4(s) + 6NaCl(aq) + 3H2O(l) + 3K3PO4(aq) + 3CaO(s) + 3CO2(g).
The heat of combustion can be calculated by subtracting the sum of the standard enthalpies of formation of the reactants from the sum of the standard enthalpies of formation of the products. For the combustion of C3H6 (propene) to CO2 and H2O, the heat of combustion would be calculated as follows: Heat of combustion = [(-394 kJ/mol) + (-285.8 kJ/mol)] - 20.6 kJ/mol = -660.4 kJ/mol.
The sample with the greatest mass at STP would be the one with the highest molar mass, as 1 mole of any substance at STP occupies the same volume (22.4 L). Among the given options, the sample with Cl2 gas (molar mass = 70.9 g/mol) would have the greatest mass.
Under the same conditions of temperature and pressure, the gas that would behave most like an ideal gas is hydrogen gas (H2g). This is because hydrogen has the smallest molar mass among the given options, leading to weaker intermolecular forces and closer adherence to ideal gas behavior.