This is the iodhydric acid.
KI + CH3COOH --> HI + CH3COO-K+ ROOH + 2HI --> ROH + H2O + I2 TITRATION WITH SODIUM THIOSULPHATE TO DERIVE THE PEROXIDE VALUE 2NA2S2O3 + I2 (PURPLE) --> NA2S4O6 + NaI (COLOURLESS)
Produces Calcium chloride and Water.2 HCl + Ca(OH)2 ----> CaCl2 + H2O
The chemical reaction is:2 HI + Br2 = 2 HBr + I2
The reaction between potassium iodide (KI) and hydrogen peroxide (H2O2) can form iodine (I2), water (H2O), and potassium hydroxide (KOH). The balanced chemical equation is: 2KI + H2O2 → I2 + 2H2O + 2KOH
The balanced chemical equation for the reaction between HI and KOH is: HI + KOH --> KI + H2O. In this reaction, hydrogen iodide (HI) reacts with potassium hydroxide (KOH) to form potassium iodide (KI) and water (H2O). The equation is balanced in terms of atoms and charge.
HI + OH- -> H2O + I-
HI
Balanced:2 HI ----> H2 + I2
The balanced equation for hydrogen and iodine reacting to form hydrogen iodide is: H2 + I2 -> 2HI.
The balanced chemical equation for hydroiodic acid (HI) and calcium hydroxide (Ca(OH)2) is: 2 HI + Ca(OH)2 → CaI2 + 2 H2O
The balanced chemical equation for the reaction of hydroiodic acid (HI) with calcium hydroxide (Ca(OH)2) is: 2HI + Ca(OH)2 → CaI2 + 2H2O
The balanced equation for the reaction between hydroiodic acid (HI) and calcium hydroxide (Ca(OH)2) is 2HI + Ca(OH)2 -> CaI2 + 2H2O.
The balanced chemical equation for the reaction of zinc with hydrochloric acid is: Zn + 2HCl → ZnCl2 + H2 This equation is balanced because it shows that one atom of zinc reacts with two molecules of hydrochloric acid to produce one molecule of zinc chloride and one molecule of hydrogen gas.
In this context, the "E" in the equation y = 6E-0.5x + 0.0029 represents scientific notation. It is used to denote a number in the form of a * 10^b, where 'a' is the coefficient and 'b' is the exponent. Therefore, 6E-0.5 can be rewritten as 6 * 10^(-0.5). This indicates that the coefficient is 6 and the exponent is -0.5.
It is not a chemical reaction; HI is dissolved in water.
The balanced equation for the reaction between hydrogen gas (H2) and iodine gas (I2) to form hydrogen iodide gas (HI) is: H2 + I2 → 2HI