39/18 Ar --> 35/16 S + 4/2 He
All you do for any alpha decay equation is subtract 2 from the bottom fraction and subtract 4 from the top fraction. Then you get the bottom number fraction and look for that number on the 'Periodic Table of Elements' and you place the subtracted fraction after the arrow and add the symbol of the element in front of it. Some problems are also shown like this:
39/18 Ar --> 35/16 S + 4/2 He
On problems like these, all you simply do is look at Ar and S. If you add 2 to the bottom fraction of S and 4 to the top fraction of S, you get 39/18 Ar. So all you have to add at the end is 4/2 He.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
Sure, the balanced alpha decay equation of radon-86 is: $$ _{86}^{222}\text{Rn} \rightarrow _{84}^{218}\text{Po} + _{2}^{4}\text{He} $$
The equation for the alpha decay of 210Po is: 84210Po --> 82206Pb + 24He representing the alpha particle as a helium nucleus. 206Pb, the daughter atom, is stable.
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
Lead-210 decays by alpha or beta decay. The equation for the alpha decay of 210Pb is: 82210Pb --> 80206Hg + 24He representing the alpha particle as a helium nucleus. The equation for the beta decay of 210Pb is: 82210Pb --> 83210Bi + -10e where the -10e is an electron.
Uranium-239 does NOT decay by alpha decay, it decays only by beta and gammadecay.
The equation for the alpha decay of 213At: 85213At --> 83209Bi + 24He where the alpha particle is represented as a helium nucleus.
The equation for the alpha decay of 265Bh is:107265Bh --> 105261Db + 24He where the 24He is an alpha particle or helium nucleus.
The equation for the alpha decay of 222Rn is: 86222Rn --> 84218Po + 24He Where He represents the alpha particle, which can also be viewed as a Helium nucleus.
parent element
The alpha decay of uranium-237 can be represented by the following equation: [^{237}{92}U \rightarrow ^{233}{90}Th + ^{4}_{2}He] This means that uranium-237 decays into thorium-233 and emits an alpha particle (helium-4 nucleus).
The alpha decay of calcium-42 results in the emission of an alpha particle (helium nucleus) from the nucleus. The equation for this decay is: ( \require{cancel} \require{mhchem} \ce{^{42}{20}Ca -> ^{4}{2}He + ^{38}_{18}Ar} )
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
The equation for alpha decay of mercury-201 is: ^201Hg -> ^197Au + ^4He This means that mercury-201 decays into gold-197 and helium-4 by emitting an alpha particle.