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What is the Kinetic Energy of the trolley at the top of the ramp if a trolley of mass is 25Kg and is released from the top of a ramp which stands at a height of 3m?
Wiki User
∙ 14y ago
What is the Kinetic Energy of the trolley at the top of the ramp if a trolley of mass is 25Kg and is released from the top of a ramp which stands at a height of 3m?
Mass = 25 Kg
Height = 3 m
This is an energy problem. At the top of the ramp, the trolley is at rest and 3m above the base line.
Potential Energy = Weight * height
Weight = mass * acceleration due to gravity
Acceleration due to gravity = 9.8m/s^2
Potential Energy = 25 kg * 9.8m/s^2 * 3 m
Potential Energy = 735 Joules
When the trolley reaches the bottom of the ramp, all the potential energy has been converted to Kinetic energy.
Potential Energy = 735 Joules = Kinetic energy
Kinetic energy = ½ * mass * velocity^2
Kinetic energy = ½ * 25 * V^2 = 735 multiply 735 by 2 and divide by 25
V^2 = 58.8
V = 7.67 m/s
Wiki User
∙ 14y ago
The kinetic energy of the trolley at the top of the ramp is equal to the potential energy it had at the top. The potential energy can be calculated using the formula PE = mgh, where m is the mass (25 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the ramp (3 m). Thus, the potential energy at the top is 259.813 = 735.75 J, which is also the kinetic energy at the top of the ramp.
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