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I've been looking up the same thing for part of a stats module I do in my nutrition course. This is what I've found - no guarantee it's right but might help a bit. sampling error ∝ 1/√n ∝ means varies directly as so SE = k/√n where k is an unknown constant if we have the size of the sample, n, and the sampling error for one case in a study (which in my question we are given) we can calculate k and get the formula for that study. In my question: for 48 subjects the sample error is 0.3mmol/l. We are asked to find how many subjects would be required to get the sampling error down to 0.1mmol/l. SE = 0.3, n = 48 so 0.3 = k/√48 k = 0.3 * √48 k = 2.078 So in this case, SE = 2.078/√n. K IS NOT ALWAYS GOING TO BE THIS NUMBER!!! You'll need to work it out each time as I dont think it will always be the same. Now work backwards to find n when SE = 0.1mmol/l 0.1 = 2.078/√n √n = 20.78 n = (20.78)2 = 432 So to get a sampling error of 0.1mmol/l we would need 432 subjects. Hope this helps! Jen xx

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16y ago
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6mo ago

The formula for sampling error is calculated as the difference between a population parameter and a sample statistic. It is typically represented as the margin of error, which is calculated by multiplying the standard error by a critical value from the standard normal distribution. Sampling error quantifies the amount of variability expected between different samples drawn from the same population.

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Q: What is the Formula for sampling error related to biostatistics?
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