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The average value of an a.c. voltage or current, over a complete cycle, is zero. For this reason, the average value is normally quoted over a half cycle and, for a sinusoidal waveform, is equal to 0.637 Vmax or 0.637 Imax.

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12y ago
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1mo ago

The average value of an AC waveform over a half cycle is zero. This is because the positive and negative values of the waveform cancel each other out over a complete cycle, resulting in a net average of zero over a half cycle.

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14y ago

Average value of AC over a half cycle is 2/Pi(Imax) for sinusoidal and cosine functions. Where Imax is the amplitude of the function, and is the final value is not effected by the period.

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12y ago

Zero

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Q: What is the Average value of AC over a half cycle?
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Related questions

The effective value of ac voltage is calculated as?

EFFECTIVE HOW ABOUT AVERAGE .639 of peak.AnswerThe 'effective' value of an a.c. voltage (or current) is the same as its 'root-mean-square' (r.m.s.) voltage which, for a sinusoidal waveform, is 0.707 Umax.The 'average' value of an a.c. voltage (or current) is zero over a complete cycle, or 0.639 Umax, over half a cycle (usually applied to rectified waveforms).


What is link between maximum current and average current?

You are, presumably, referring to alternating current, in which case the 'maximum' current is the peak or amplitude of the waveform. The 'average' value of current is zero, because the average value of the first half of each cycle is negated by the average value over the second half of each cycle. This is why a.c. currents and voltages are always expressed in 'root-mean-square' (r.m.s.) values which is the value of an a.c. current that does the same amount of work as a given value of d.c. current. The r.m.s. value for a sinusoidal current (and voltage, as voltage and current are proportional) is 0.707 times the peak or maximum value.


What is average value in alternate voltage?

The term is 'alternating voltage', not 'alternate voltage'. For an a.c. voltage or current, the average value is taken over half its wavelength because, over a complete wavelength it is, of course, zero. For a sine wave, the average value (over half a wavelength) is 0.637 Vmax or 0.637 Imax.


How do you convert into maximum current if the average current is given?

Presumably you are referring to an a.c. current?If so, then the average value of an a.c. current is zero so, clearly, you cannot determine its maximum value.However, average current is more-usually applied over half a cycle, in which case, for a sinusoidal current, this value is 0.637 Imax. So the maximum current will be the average value, divided by 0.637.


What is the average value of a pure sine wave?

The average value of a sine wave is 0. That's by integrating the function over a whole (or any integer number of whole-) cycles and dividing by the total time, n*T. In a "pure" sine wave, i.e., one with zero distortion, one half cycle has some total integral that's a sum of positive values, while the second half cycle is all *below the axis*, so negative in value and symmetrical with the first half. So when you add the two (or n*2) half cycles--which is integration--you get a sum of zero. No matter the frequency, or amplitude of the sine wave.


What is the main differences between RMS value and average value?

RMS stands for root mean square. This is done so that negative values are then treated as positive values. In AC power for example, the voltage varies between a negative and a positive value. The number is squared and then the square root of this value is taken and the mean (average) of these numbers gives the answer. For example -40 is squared to become 1600 and then the square root of 1600 is taken to become 40 (a negative number becomes a positive number).If this wasn't done then the average value of AC power would be zero.


What is the relationship between peak rms and average values of an ac voltage?

Peak voltage of an AC voltage is the value at its highest or lowest point.RMS (Root Mean Square) voltage of an AC voltage is a mathematical derivation involving the square root of the average value of the squares of samples of the voltage as the sample interval approaches zero.Average voltage is simply that - the average or mean voltage.For a true sine wave, RMS and average are equivalent, but they are not equivalent when the wave is distorted, or has some other shape such as triangular.RMS is the best way to measure an AC voltage, as it gives you a true reading of the amount of power that the voltage can deliver.One issue with non-RMS AC meters is that they typically measure the rectified, filtered peak value and then compensate by dividing by 1.4. This is not correct unless the voltage is a sine wave.AnswerThe peak value of an a.c. voltage or current is the amplitude of that voltage or current waveform -i.e. the maximum value of voltage or current in either the positive or the negative sense.The root-mean-square (rms) value of an a.c. voltage or current. For a sinusoidal waveform, the rms value is 0.707 times the peak value (amplitude). A.C. voltages or currents are always quoted in rms values unless otherwise specified.The average value of an a.c. voltage or current is zero over one complete cycle so, when used, it applies only over one half cycle. Therefore, the average value for one-half cycle of a sine wave is 0.637 times the peak value. Average values are of little relevance to a.c. calculations.


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