The demand load would be 12 kW. When you talk about line and neutral you are referring to the voltage that the equipment operates on. In North America, an electric kitchen range operates on two voltages 120/240 volts. The 240 volts is obtained across two breakers in the distribution panel and the 120 volts is obtained between either 240 volt leg and the neutral. On a range of this size the 120 volts is usually used for the clock and controls for the range. The range at maximum would draw 50 amps, fed by a two pole 50 amp breaker using a #6 copper conductor with an insulation factor of 90 degrees C. The range will have an internal breaker or fuse to protect the 120 volt circuit.
In a 240V system, 1 kW is equal to approximately 4.17 amps. This calculation is done by dividing the power in watts (1000 watts for 1 kW) by the voltage (240V) in the system.
For an 8 kW heater, you would typically use 10-gauge wire with a 30 amp breaker. Always consult the manufacturer's specifications and local electrical codes to ensure proper sizing and installation.
A 20 amp breaker can handle up to 2400 watts per hour (20 amps x 120 volts = 2400 watts).
8 amps at 240 volts is equal to 1920 watts. This calculation is done by multiplying the current (8 amps) by the voltage (240 volts) to get the power in watts.
AWG #3 copper.
The demand load would be 12 kW. When you talk about line and neutral you are referring to the voltage that the equipment operates on. In North America, an electric kitchen range operates on two voltages 120/240 volts. The 240 volts is obtained across two breakers in the distribution panel and the 120 volts is obtained between either 240 volt leg and the neutral. On a range of this size the 120 volts is usually used for the clock and controls for the range. The range at maximum would draw 50 amps, fed by a two pole 50 amp breaker using a #6 copper conductor with an insulation factor of 90 degrees C. The range will have an internal breaker or fuse to protect the 120 volt circuit.
120 15 amp service ? 210 7 amp service ?
10 mm2 cross section should be sufficient (#6 wire?)
A breaker protects the wire size of the feeder that is connected to it. The amperage of the load must be found. Without a voltage stated the amperage from the wattage given can not be calculated. The equation for amperage when the kw is given is A = kW x 1000/1.73 x volts x pf. The pf constant to use is .9.
In a 240V system, 1 kW is equal to approximately 4.17 amps. This calculation is done by dividing the power in watts (1000 watts for 1 kW) by the voltage (240V) in the system.
For an 8 kW heater, you would typically use 10-gauge wire with a 30 amp breaker. Always consult the manufacturer's specifications and local electrical codes to ensure proper sizing and installation.
I=270000/380/1.732 I=410A USE: 500A CIRCUIT BREAKER
the given kw Divide by the your voltage
3000 / 240 = Amps. You de-rate a breaker by 20 % for continuous load like an oven. You could get by with a 20 Amp breaker and 12 AWG wire. However, I would recommend 30 Amps and 10 AWG for an oven for the long run.
This formula will give you the amperage I = kw x 1000/1.73 x E x pf (pf = power factor). Take the amperage and multiply it by 125%. This will give you the breaker size that you need.
14 AWG wire normally supplies 15 amps. Watts = Volts x Amps x Power Factor. Power Factor has a maximum value of one. If you have a 120 volt circuit that would be 15 x 120 = 1800 watts or 1.8 KW. For a 240 volt circuit 3.6 KW.