A chlorine atom gains an electron when it becomes an ion. This means it has been reduced because there is a decrease in oxidation state from 0 to -1.
Technically, Francium would be the most easily reduced metal, however most people don't consider it to due its radioactivity. Next up though is Cesium. Rubidium is more easily reduced then potassium, and cesium is more easily reduced then rubidium.
Iodine ion is not consumed; in the first step the iodine ion is oxidized to iodine, in the second step iodine is reduced to iodine ion.
Cr3+ is reduced to Cr2+ because it gains an electron, which leads to a decrease in oxidation state. Conversely, the electron is being donated, so the species donating the electron is oxidized.
Oxygen is transported as reduced hemoglobin in the blood. In this form, hemoglobin has bound to oxygen molecules and is carrying them to tissues throughout the body.
Cu2+
Yes, permanganate ions (MnO4-) can oxidize the chloride ion (Cl-) to Cl2 in acidic solution. In this process, permanganate is reduced to Mn2+. The overall reaction is 8H+ + 2MnO4- + 10Cl- → 2Mn2+ + 8H2O + 5Cl2.
No. It is reduced since it is a negative ion.
No it is not. However, it is easily oxidised.
A chlorine atom gains an electron when it becomes an ion. This means it has been reduced because there is a decrease in oxidation state from 0 to -1.
Technically, Francium would be the most easily reduced metal, however most people don't consider it to due its radioactivity. Next up though is Cesium. Rubidium is more easily reduced then potassium, and cesium is more easily reduced then rubidium.
Plastic can easily be reduced by using reusable bags.
No, The fluoride ion is a reduced form of fluorine.
I have a 2006 Saturn ion. The reduced engine power light came on and the car still runs but will not accelerate and only goes 30mph
When a tin ion is reduced, it gains electrons and its oxidation number decreases. Tin typically forms a +4 oxidation state in compounds, so upon reduction, it becomes tin with a +2 oxidation state.
Iodine ion is not consumed; in the first step the iodine ion is oxidized to iodine, in the second step iodine is reduced to iodine ion.
Oxygen will be reduced in the reaction with sodium because it gains electrons to form the oxide ion (O2-).