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Yes, GeBr (germanium bromide) is a polar molecule. This is because the Ge-Br bond is polar due to the difference in electronegativity between germanium and bromine.
The difference electronegativity values of sodium and bromine are; Sodium(Na) 0.9, Bromine(Br) 2.8 thus a difference of 1.9.
Pd , Co are transition elements.
Yes, HBr is a polar molecule since hydrogen bromide has a significant difference in electronegativity between hydrogen and bromine atoms, causing an uneven distribution of charge leading to a partial positive charge on hydrogen and a partial negative charge on bromine.
Yes, HSiBr3 is a polar molecule. This is because of the difference in electronegativity between silicon (Si) and bromine (Br) causes an uneven distribution of electron density in the molecule, leading to a net dipole moment.
The electronegativity difference between Mg and Br is approximately 1.0. Mg has an electronegativity value of around 1.2, while Br has an electronegativity value of around 2.8. This difference in electronegativity indicates that a bond between Mg and Br would have a somewhat polar character.
Br-Cl has a more polar bond because chlorine is more electronegative than iodine, resulting in a greater difference in electronegativity between the two elements. This difference in electronegativity leads to a more polar bond in Br-Cl compared to Br-I.
The electronegativity difference between aluminum (Al) and bromine (Br) in AlBr3 is around 1.1. This indicates a polar covalent bond due to the significant electronegativity difference between the two elements.
if its for apex learning then the answer is bromine
The bond between Br-I is more polar than the bond between Br-Cl. This is because iodine is less electronegative than chlorine, resulting in a larger difference in electronegativity between the two atoms in the bond. Therefore, the Br-I bond will exhibit stronger polarity.
Fluorine is the strongest oxidizing agent among the elements chlorine, fluorine, iodine, and bromine. It has the highest electronegativity and is most effective at accepting electrons in a redox reaction.
The bond between Ba and Br demonstrates that the boundaries between bond types are not clear cut because Ba and Br have a significant electronegativity difference, indicating an ionic bond. However, due to the large size of Ba and the polarizability of Br, some covalent character can also be present in the bond, blurring the distinction between purely ionic and covalent bonds. This shows that the electronegativity difference alone is not always sufficient to classify a bond type definitively.
The electronegativity difference of bromide (Br) is 0.97. The electronegativity of bromine is 2.96 and the electronegativity of chlorine is 3.93.
The bond between Cl and Br is ionic, as Cl is a halogen with a high electronegativity and tends to gain an electron to form a negative ion (Cl-) while Br is a halogen that tends to lose an electron to form a positive ion (Br+).
The electronegativity difference between sodium (Na) and bromine (Br) is about 2.8. This indicates that bromine is significantly more electronegative than sodium, leading to the formation of an ionic bond when they react to form sodium bromide.
The electronegativity from least to highest : Ba, Be, Bi, B, Br The electronegativity of an element is a measurement of how its atoms attract electrons. This is based on the atomic weight (width of the atomic nucleus) and the distance of its valence electrons from the nucleus. As displayed on the Periodic Table, elements generally increase in electronegativity as you move across (left to right), and decrease as you go down the table. (Only aluminum does not follow this in this set of elements.) (see related link)
The bond between two Br atoms is considered nonpolar because both atoms are the same element with identical electronegativity values. This means that the electrons are equally shared between the two atoms, resulting in a symmetrical distribution of electron density across the bond.