Fluorine...
it has seven valence electrons and really wants to achieve noble gas configuration (8 out of 8 possible valance electrons). It already has seven and since it is so close to eight, it is very attached to them. It refuses to give them up easily. The more an element "wants" it's electrons the higher ionization energy it will have.
http://www.800mainstreet.com/4/0004-002-Periodic.html
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
Core electrons. Probably the 1s level would require the most ionization energy to pull these electrons.
The first ionization energy decrease from top to bottom for the noble gas family.
This is the alkali metals family; the ionization energy is lower for these chemical elements.
Ionization can have any number of causes, resulting in any number of ionization states ranging from ±1 to ±(atomic number) for any given atom. In the given context, however, I would assume the actual question intended is, "What is the preferential ionic state of ionically bonded atoms in the VIA periodic family?" The answer to this question is -2.
the lowest ionization energy in IA :hydrogen ,lithiun ,sodium and potassium
The element that has a lower first ionization energy than aluminum (Al) is magnesium (Mg). Magnesium is one period above aluminum on the periodic table, and as you move down a group or family, the ionization energy tends to decrease.
Core electrons. Probably the 1s level would require the most ionization energy to pull these electrons.
The first ionization energy decrease from top to bottom for the noble gas family.
The biggest element in the alkali family is cesium. It has the largest atomic radius and is the most reactive alkali metal due to its large size and low ionization energy.
This is the alkali metals family; the ionization energy is lower for these chemical elements.
Ionization can have any number of causes, resulting in any number of ionization states ranging from ±1 to ±(atomic number) for any given atom. In the given context, however, I would assume the actual question intended is, "What is the preferential ionic state of ionically bonded atoms in the VIA periodic family?" The answer to this question is -2.
An element with a single electron in its highest energy level is likely an alkali metal. Alkali metals like lithium, sodium, and potassium have one electron in their outer energy level, making them highly reactive and likely to form ionic bonds.
The element is 'argon' and belongs to noble gas family.
There is a slight decrease in ionization energy when moving from Group 2 to Group 13 due to the introduction of a new subshell (s to p transition), causing increased electron shielding. Additionally, there is a slight decrease in ionization energy when moving from Group 15 to Group 16 due to the stable half-filled p orbital that requires more energy to remove an electron.
The first ionization energy generally decreases from top to bottom in the alkali metal family. This is due to the increase in atomic size and the shielding effect from inner electrons, which makes it easier to remove the outermost electron.
The ionization energy generally decreases down a group in the periodic table within the same chemical family. This is because as you move down a group, the outermost electrons are located in higher energy levels, making them farther from the nucleus and thus easier to remove.