V=IR
To calculate your voltage drop (V), you multiply your resistance (R, measured in Ohms) and current (I, measured in Amps [A]) by each other the. The number you are left with should be your voltage drop.
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Voltage is a measure of electrical potential difference between two points in a circuit. It is often represented by the symbol "V" and is measured in volts (V). Voltage determines the force with which electric charges flow in a circuit.
To measure the voltage drop in a circuit 1st we have to measure the each resistance, for which drop is occurring and than we have to measure current flowing through each resitance. After that we have to multiply current and resistance for each resistance which will ngive voltage drop in each resistance. Now to have total resistance we have to sum up all the voltage drops in whole circuit.
1 V = 1 J/C (1 joule per coulomb). That is, if there is a potential difference (or a "voltage") of one volt, you will require (or gain, depending on the sign) 1 joule of energy to move a charge of 1 coulomb across that potential difference.
for calculating the voltage drop in ckt first of all you have to calculate the total resistance of the ckt as well as total current also then applying ohm's law v=IR u can calculate the voltage drop across a ckt
While the answer is correct you might investigate thevenin theory.
1 kg m2 / (A s3)
Answer
A volt is defined as 'the potential difference between two points such that the energy used in conveying a charge of one coulomb from one point to the other is one joule'.
Since the voltage drop occurs across both conductors, we must take the resistance of both conductors in the cable into account. So, if the resistance of one conductor is R, then the total voltage drop along that cable will be:
Voltage drop = I x I x 2R
No, the current is equal to the power (watts) divided by the voltage, based on the formula: current = power / voltage. Voltage divided by watts does not equal current.
A voltage of 13.8 kV is equal to 13,800 volts.
If you know the voltage you can calculate the amps. . Ampere I = power P / voltage V .
Voltage is equal to amperage time resistance. V=IR Therefore, I'd say voltage times amperage is equal to amperage squared times resistance. VI=IIR Really there's no point in multiplying the two. However, if you were to divide voltage by amperage, you would have the resistance of the circuit. V/I=R
The phase voltages in a balanced 3-phase system are equal to the line voltages divided by the square root of 3. Therefore, if the line voltage is 100 volts, the phase voltage would be approximately 57.7 volts.