Sodium sulfate solution is neutral; the red litmus is purple.
Blue litmus turns red in acid. Sodium carbonate solution is alkaline (basic), so nothing will happen when blue litmus is put into this. Red litmus will turn blue if added to sodium carbonate.
Red litmus paper turn blue in basic solutions; sodium carbonate solution is basic.
Iron does not displace sodium from a salt solution because it is not reactive enough. Iron does, however, displace Cu from a copper sulphate solution.
fehling a is copper sulphate and fehling b is alkaline solution of sodium pottasium tartarate
Mercuric chloride is a preservative that helps prevent contamination, sodium sulfate is a sedimentation agent that helps in the formation of a sediment layer for blood cell counts, and sodium chloride maintains the osmotic balance of the solution.
To distinguish between these solutions: Copper sulphate solution will be blue in color. Sodium chloride solution will not exhibit any color and will form white crystals upon drying. Sodium nitrate solution will not exhibit any color and is typically used as an oxidizing agent. Sodium sulphate solution will not exhibit any color and may form white crystals upon drying.
Fehling's solution is made up of two separate solutions: Fehling's A (copper sulfate solution) and Fehling's B (potassium sodium tartrate and sodium hydroxide solution). When combined in equal parts, these solutions are used to test for the presence of reducing sugars like glucose in a chemical sample.
When iron sulfate and sodium carbonate are mixed, iron carbonate and sodium sulfate are produced. Iron carbonate is a solid precipitate that can be formed during the reaction, while sodium sulfate remains in solution.
Sodium chloride water solution is neutral.
The solution is colorless.
Blue litmus turns red in acid. Sodium carbonate solution is alkaline (basic), so nothing will happen when blue litmus is put into this. Red litmus will turn blue if added to sodium carbonate.
Sodium chloride solution is neutral.
To find the molarity, first calculate the number of moles of sodium sulphate using its molar mass. Sodium sulphate's molar mass is 142.04 g/mol. Next, divide the number of moles by the volume in liters (125 ml = 0.125 L) to get the molarity. This will give you the molarity of the sodium sulphate solution.
Red litmus paper turn blue in basic solutions; sodium carbonate solution is basic.
A white precipitate of barium sulphate is formed when sodium sulphate solution is added to barium chloride solution. This is due to the formation of an insoluble salt, barium sulphate, which appears as a white solid in the solution.
Nowhere. I assume you are talking about mixing solutions. The sodium ions and sulpahate ions remain in solution.
Yes, it is true. The equation of reaction is :- BaCl2 + Na2SO4 --------> 2NaCl(aq.) + BaSO4 where solution is of sodium chloride and Barium sulphate settles down at the bottom as precipitate