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I think you are talking about it's internal resistance or it's ability to supply a current to a load without significant drop in voltage.

Experiment to find EMF of unknown cell

The 1 Metre scaled potentiometer is placed across a cell of known EMF and the 'jockey' or slider connected to one terminal of a galvanometer. The second cell is wired with similar polarity to the first cell and connected from the other side of the galvo to the common negative terminal of the two cells.

The slider of the potentiometer is progressively moved up from zero until the galvo shows no current. The EMF of the unknown cell is now a direct proportion to the reading in cm read of the metre scale.

Example

If the known cell has EMF of 3 volts and the galvo balances at 50cm then the unknown cell has EMF of1.5Volts

Dry cells used in flashlights have a fairly high internal resistance whereas a Lead acid car cell has a very low internal resistance allowing the starter motor to draw hundreds of Amperes without volt drop.

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14y ago
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1mo ago

Comparing the EMF of two cells using a potentiometer can help determine the difference in voltage output between the two cells. This information is useful in determining the efficiency of the cells, identifying faulty cells, or selecting the cell with the higher EMF for a particular application. Additionally, it can be used in educational settings to demonstrate how potentiometers work to measure EMF variances.

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Q: What are the applications of comparing Emf of two cells with the help of potentiometer?
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