To calculate the amount of helium in the balloon, we need to convert the mass of helium gas to moles using the molar mass of helium. The molar mass of helium is 4 g/mol. So, 0.54 grams of helium is equal to 0.54/4 = 0.135 moles of helium. Finally, we can use Avogadro's principle to convert moles to the number of helium atoms present in the balloon.
4 g or helium is 1 mole. So, 0.12 g of helium is 0.03 mole
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
The molar mass of helium is approximately 4.0026 g/mol. Therefore, the mass of 18.8 moles of helium atoms would be 18.8 moles * 4.0026 g/mol ≈ 75.2 grams.
Helium exists as a monatomic noble gas. Its atomic mass is 4.0 as can be obtained from the periodic table. The amount of helium in a 205g pure sample is given by 205/4.0 which equates to roughly 51 moles.
This amount of helium gas is approximately 0.54 g. Helium is a very light gas that has a low density at standard conditions.
To find the number of moles of Helium in 6.46 g, you need to divide the given mass by the molar mass of Helium (4 g/mol). 6.46 g / 4 g/mol = 1.615 moles of Helium.
To calculate the amount of helium in the balloon, we need to convert the mass of helium gas to moles using the molar mass of helium. The molar mass of helium is 4 g/mol. So, 0.54 grams of helium is equal to 0.54/4 = 0.135 moles of helium. Finally, we can use Avogadro's principle to convert moles to the number of helium atoms present in the balloon.
To find the number of moles of helium in the balloon, you need to divide the mass of helium by its molar mass. The molar mass of helium is approximately 4 g/mol. Therefore, 0.46 g of helium is equal to 0.46 g / 4 g/mol = 0.115 mol of helium in the balloon.
4 g or helium is 1 mole. So, 0.12 g of helium is 0.03 mole
1 mole of helium weighs 4.0026 g So. 18.8 of helium will weigh 75.25 g
The molar mass of helium is approximately 4.0026 g/mol. Therefore, the mass of 18.8 moles of helium atoms would be 18.8 moles * 4.0026 g/mol ≈ 75.2 grams.
Helium exists as a monatomic noble gas. Its atomic mass is 4.0 as can be obtained from the periodic table. The amount of helium in a 205g pure sample is given by 205/4.0 which equates to roughly 51 moles.
To find the number of moles present in 205 g of helium, we need to use the molar mass of helium, which is approximately 4 g/mol. Divide the given mass by the molar mass to get the number of moles. In this case, 205 g / 4 g/mol = 51.25 moles of helium.
To double the volume of the balloon, you would need to add an additional 8.00 g of helium gas. This is because the ideal gas law states that the volume of a gas is directly proportional to the amount of gas present, assuming constant temperature and pressure. So, if you double the amount of gas, you double the volume of the balloon.
4 g of helium is equivalent to 1 mole of helium
To calculate the number of moles, you need to divide the given mass by the molar mass of helium. The molar mass of helium is approximately 4 g/mol. Therefore, the number of moles in 205g of helium would be 205g / 4g/mol = 51.25 mol.