The relative number of moles of hydrogen to moles of oxygen that react to form water represents the stoichiometry of the chemical reaction according to the balanced equation. This relationship reflects the proportions in which the reactants combine to form the products.
Carbon dioxide is the limiting reagent.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
The number of moles in exactly 64 grams of oxygen (O2) is two.
The number of moles is 0,4375.
0.678 - 0.682
After the reaction is complete, all of the calcium will react with 3.165 mol (since calcium and oxygen react in a 1:1 ratio) of the oxygen gas. This means that there will be 4.00 mol - 3.165 mol = 0.835 mol of oxygen gas left over.
For the reaction SO2 + O2 -> SO3, the stoichiometry is 1:1. So, if 4 moles of SO2 are oxidized, then 4 moles of O2 are required for the complete reaction.
The relative number of moles of hydrogen to moles of oxygen that react to form water represents the stoichiometry of the chemical reaction according to the balanced equation. This relationship reflects the proportions in which the reactants combine to form the products.
For every mole of oxygen consumed in the reaction 2H2 + O2 -> 2H2O, two moles of water are produced. Therefore, if 0.633 moles of oxygen are consumed, the number of moles of water produced would be 2 x 0.633 = 1.266 moles.
Carbon dioxide is the limiting reagent.
Since acetylene (C2H2) has a stoichiometry of 2 moles of acetylene to produce 2 moles of CO2, three moles of acetylene would produce 3 moles of CO2. The reaction with excess oxygen ensures that all the acetylene is fully converted to CO2.
When 5.5 moles of oxygen react, the same number of moles of water will be formed. This is based on the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction of calcium with oxygen is 2Ca + O2 -> 2CaO. This means that 2 moles of calcium react with 1 mole of oxygen. Using this ratio, if 6.33 moles of calcium react, they will use 3.165 moles of oxygen. Since we only have 4.00 moles of oxygen, there is excess oxygen left over. So, 0.835 moles of oxygen will be left over after the reaction.
For every mole of potassium chlorate that decomposes, three moles of oxygen are produced. Therefore, if 7.5 moles of potassium chlorate decompose, 22.5 moles of oxygen would be produced (7.5 moles x 3).
The number of moles in exactly 64 grams of oxygen (O2) is two.
The number of moles is 0,4375.