Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
To find the moles of H2O produced, first calculate the moles of O2 present in 355 g using its molar mass. Then, use the mole ratio from the balanced chemical equation of the reaction to determine the moles of H2O produced.
The reactants in this equation are hydrogen gas (H2) and oxygen gas (O2).
The balanced equation for the reaction between O2 and H2 is 2H2 + O2 -> 2H2O.
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
It is not balanced. There should be a 2 in front of H2 and H2O
The balanced symbol equation for water is 2H2 + O2 -> 2H2O.
2 H2 + O2 = 2 H2O
= H2+O2 =2H2+O2=2H2O
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
The chemical equation given “H2 + O2 -> H2O” is not balanced. To balance it, you need to modify the coefficients in front of the molecules. The balanced equation should be: "2H2 + O2 -> 2H2O" where you have two molecules of hydrogen gas reacting with one molecule of oxygen gas to produce two molecules of water.
Water decomposes into Oxygen and Hydrogen gases, each of which is a 2 atom molecule: H20 -> H2 + O2 BUT that's not balanced - there's Oxygen 'appearing' from nowhere on the right side so to balance it (2) H2O -> H2 + O2 But now we have 4 Hydrogens on left and only two on right (2) H2O -> (2)H2 + O2 4 hydrogens and 2 oxygen - > 4 hydrogens and 2 Oxygens Balanced!
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
The balanced chemical equation for the reaction between C2H5OH (ethanol) and H2O (water) is: C2H5OH + H2O → CH3COOH + H2 This reaction produces acetic acid (CH3COOH) and hydrogen gas (H2) as products.
Water (H2O) is made of 2 molecules of hydrogen and one oxygen. When you separate water into a gaseous state by electrolysing the water, you have separated the oxygen and hydrogen molecules. If you were to bubble that gas (Brown's gas) through water, the water absorbs the extra 2 molecules of hydrogen and one molecule of oxygen. 2H2O + 2H2 + O2 = 2[H3O]+ + 2[OH]-