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How many moles O2 must react with excess H2 to form 7.89 mol H2O?
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
How do you balance the chemical equation O2 plus H2?
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
How many moles of H2O are product from reaction of 355 g of O2?
To find the moles of H2O produced, first calculate the moles of O2 present in 355 g using its molar mass. Then, use the mole ratio from the balanced chemical equation of the reaction to determine the moles of H2O produced.
In the equation 2 H2 plus O2 --- 2 H2O what substances are the reactants?
The reactants in this equation are hydrogen gas (H2) and oxygen gas (O2).
What is the balanced equation for the reaction between 02 and H2?
The balanced equation for the reaction between O2 and H2 is 2H2 + O2 -> 2H2O.
Is H2O-H2 plus O2 a balanced chemical equation?
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
What is the mistake in H2 plus O2 equals H20?
It is not balanced. There should be a 2 in front of H2 and H2O
What is the balanced symbol equation of water?
The balanced symbol equation for water is 2H2 + O2 -> 2H2O.
Write a balanced equation for the ignition reaction of hydrogen in air?
2 H2 + O2 = 2 H2O
Balance the equation1.H2+ O2=H2O?
= H2+O2 =2H2+O2=2H2O
How many moles O2 must react with excess H2 to form 7.89 mol H2O?
Oxygen limits the reaction, so......Balanced equation. 2H2 + O2 -> 2H2O 7.89 mole H2O (1 mole O2/2 mole H2O) = 3.95 mole oxygen gas needed ------------------------------------------
3g of H2 react with 29g of O2 to give water The maximum amount of H2O formed is?
The balanced chemical equation for the reaction is 2H2 + O2 -> 2H2O. Using stoichiometry, we find that 3g of H2 will react completely with 24g of O2 to form 18g of H2O. Therefore, the maximum amount of H2O formed when 3g of H2 reacts with 29g of O2 is 18g.
What is h20 h2 o2 balanced?
The chemical equation given “H2 + O2 -> H2O” is not balanced. To balance it, you need to modify the coefficients in front of the molecules. The balanced equation should be: "2H2 + O2 -> 2H2O" where you have two molecules of hydrogen gas reacting with one molecule of oxygen gas to produce two molecules of water.
Balanced reaction for the decomposition of water?
Water decomposes into Oxygen and Hydrogen gases, each of which is a 2 atom molecule: H20 -> H2 + O2 BUT that's not balanced - there's Oxygen 'appearing' from nowhere on the right side so to balance it (2) H2O -> H2 + O2 But now we have 4 Hydrogens on left and only two on right (2) H2O -> (2)H2 + O2 4 hydrogens and 2 oxygen - > 4 hydrogens and 2 Oxygens Balanced!
What is the percent yield of h2o if 58g h2o are produced by combining 60g o2 and 7g h2?
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
How do you balance the chemical equation O2 plus H2?
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
How do you balance C2H5OH plus H2O?
The balanced chemical equation for the reaction between C2H5OH (ethanol) and H2O (water) is: C2H5OH + H2O → CH3COOH + H2 This reaction produces acetic acid (CH3COOH) and hydrogen gas (H2) as products.
