In this scenario, the glucose in sac 1 will diffuse out of the sac into the distilled water due to the concentration gradient. However, since distilled water is hypotonic compared to the 40% glucose solution, water molecules will also move into the sac via osmosis to try to balance the concentration inside and outside the sac. This will cause the sac to swell as water moves in, reaching an equilibrium point where the movement of glucose and water is balanced.
Yes, glucose can move into the cell through facilitated diffusion using glucose transport proteins on the cell membrane. The concentration gradient allows for passive transport of glucose molecules into the cell.
The percentage of carbon in glucose is 40 %.
Approximately 38% of the energy in glucose is transferred to ATP during cellular respiration. The rest of the energy is released as heat.
In cellular respiration, about 34-38% of the available energy stored in glucose is converted to ATP. The rest of the energy is released as heat.
The glucose was able to go through the sac. The glucose went from high concentration to low concentration. The glucose is permeable.
In this scenario, the glucose in sac 1 will diffuse out of the sac into the distilled water due to the concentration gradient. However, since distilled water is hypotonic compared to the 40% glucose solution, water molecules will also move into the sac via osmosis to try to balance the concentration inside and outside the sac. This will cause the sac to swell as water moves in, reaching an equilibrium point where the movement of glucose and water is balanced.
Yes, glucose can move into the cell through facilitated diffusion using glucose transport proteins on the cell membrane. The concentration gradient allows for passive transport of glucose molecules into the cell.
The statement seems incomplete. Please provide additional information or context so I can better understand the question and provide an appropriate response.
The patient should sit with the head elevated 30-40 degrees. This is done to maximize fluid drainage. A site close to the pericardial sac is chosen, and if time permits the patient is sedated.
Answer: 7 x 10-3 g glucoseProcess below:First convert 40 µmol to moles. 1 µmol = 1 x 106 mol.40 µmol x (1 mol)/(1 x 106µmol) = 4 x 10-5 molMultiply 4 x 10-5 mol by the molar mass of glucose (180.156 g/mol).4 x 10-5mol glucose x (180.156 g glucose)/(1 mol glucose) = 7 x 10-3 g glucose
To find the molarity, first calculate the number of moles of glucose in 40 g using its molar mass. Then, divide the moles of glucose by the volume of the solution in liters (1.5 L) to get the molarity.
Approximately 40% of the energy from the oxidation of glucose is transferred to ATP during cellular respiration. The rest of the energy is lost as heat.
Once digested, 100% of carbohydrates are converted to glucose. However, approximately 40% of protein foods are also converted to glucose, but this has minimal effect on blood glucose levels.
approximately 40%
About 40% of the energy derived from glucose is converted to ATP through cellular respiration. The rest is released as heat.
-40 Fahrenheit is equal to -40 Celsius.