Yes, aluminum atoms are considered to be relatively large in size compared to other elements due to their electron configuration and atomic radius.
If water continues to be heated, it will eventually reach its boiling point and transition into a gaseous phase, becoming steam.
As atoms move from solid to liquid to gas, their kinetic energy increases. In the solid phase, atoms vibrate in fixed positions with low kinetic energy. In the liquid phase, atoms have more freedom to move around and their kinetic energy increases. In the gas phase, atoms have even more kinetic energy as they move freely and rapidly.
Typically, the gas would be the solute and the liquid would be the solvent. But it really depends on what is present in the largest amount. The phase present in the largest volume is the solvent; the other is the solute.
Nonexistite. Such a compound would not be stable, unless there are additional atoms you're not telling us about. Aluminium (III) oxide, aka aluminum oxide, alumina, or corundum, would be Al2O3.
The formula for the compound would be AlCl3. This means that there is one aluminum atom for every three chlorine atoms in the compound.
It decreases. In gaseous phase the molecules are further apart than they are in the solid phase so although in solid phase the molecules are still moving minimally they haven't got the space to move around in that they would in the gaseous phase.
For aluminum sulfide (Al2S3), the ratio of aluminum to sulfur atoms is 2:3. This means that for every 3 atoms of sulfur, 2 atoms of aluminum will react. So, to produce aluminum sulfide from 1.33 x 10^24 atoms of sulfur, you would need (2/3) * 1.33 x 10^24 atoms of aluminum, which is approximately 8.87 x 10^23 atoms of aluminum.
To determine the number of aluminum atoms on each side of a balanced equation, you would need to examine the coefficients of the aluminum-containing compounds in the equation. Then, multiply the coefficient by the number of aluminum atoms in each compound. For example, in the equation 2Al + 3CuO → Al2O3 + 3Cu, there are 2 aluminum atoms on each side.
To calculate the number of aluminum atoms in 2.78g of aluminum, you first need to convert the mass to moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to determine the number of atoms. The calculation would be: (2.78g Al) / (26.98 g/mol) * (6.022 x 10^23 atoms/mol).
that would depend on the type of atoms and your definition of metallic.
Yes, aluminum atoms are considered to be relatively large in size compared to other elements due to their electron configuration and atomic radius.
Water is in the liquid phase at 1 ATM pressure and 150°C.
The correct formula for a compound formed between aluminum and fluorine with a 1:3 ratio would be AlF3. This means that one aluminum atom will combine with three fluorine atoms to form the compound.
If water continues to be heated, it will eventually reach its boiling point and transition into a gaseous phase, becoming steam.
You would need to line up about 2,500,000 aluminum atoms to match the width of a human hair. This is because the width of a human hair is typically around 70 micrometers, and an aluminum atom is about 0.28 nanometers in diameter.
The number of aluminium atoms ia 0,44638973.10e23.