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∆G = ∆H - T∆S and for it to be spontaneous, ∆G should be negative. If both ∆H and ∆S are positive, in order to get a negative ∆H, the temperature needs to be elevated in order to make the ∆S term greater than the ∆H term. So, I guess the answer would be "the higher the temperature, the more likely will be the spontaneity of the reaction."

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Q: How will temperature affect the spontaneity of a reaction positive delta h and delta s?
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How will the temperature affect the spontaneity of a reaction with positive h and s?

A high temperature will make it spontaneous.


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A high temperature will make it spontaneous.


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