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∙ 16y agoW = (1/2)kx^2
W = (1/2)(12.3)(.252)^2 //Convert cm to m
W = 0.39Nm = 0.39J
Wiki User
∙ 16y agoThe work required to stretch a spring by a certain distance is given by the equation: W = 0.5 * k * x^2, where k is the force constant of the spring and x is the distance stretched. Plugging in the values, we get W = 0.5 * 12.3 N/m * (0.252 m)^2 = 0.78 J. So, 0.78 Joules of work is required to stretch the spring by 25.2 cm.
A spring scale measures force by determining the amount of stretch or compression in a spring when an object is hung from it. It primarily measures the force of gravity acting on an object, which is commonly referred to as weight.
A spring is a good force measurer for a Newton meter because its extension is proportional to the force applied to it according to Hooke's Law. This makes it easy to calibrate and read the force applied. Additionally, springs have elasticity, enabling them to return to their original shape once the force is removed, making them reusable for multiple measurements.
The reaction of a spring is to exert a force opposite to the direction it is compressed or stretched. This is known as Hooke's Law, which states that the force exerted by a spring is proportional to the displacement from its equilibrium position. In other words, when you compress or stretch a spring, it pushes or pulls back with a force that tries to return it to its original position.
To predict how many centimeters the spring will stretch, we need to know the spring constant in N/cm and apply Hooke's Law. Hooke's Law states that the force exerted by a spring is directly proportional to its extension. By knowing the spring constant and the total mass attached, we can calculate the stretch.
Hooke's Law states that the force needed to compress or stretch a spring is directly proportional to the displacement of the spring from its equilibrium position. This means that as long as the material of the spring remains within its elastic limit, the relationship between force and displacement is linear.
The amount of force required to stretch a spring by 49 inches depends on the stiffness or spring constant of the spring. The formula to calculate this force is F = k * x, where F is the force, k is the spring constant, and x is the displacement of the spring (in this case, 49 inches). Without knowing the spring constant, the force required cannot be determined.
When you stretch a spring, it stores potential energy in the form of elastic potential energy. The spring will exert a restoring force trying to return to its original shape. The amount of force required to stretch the spring is directly proportional to the amount of deformation.
depends on the initial length of the spring, and how much force is required to stretch the spring
The force that causes a spring to stretch is called tensile force. This force is exerted when an external force is applied to the ends of the spring, causing it to elongate.
When you stretch a spring, two main forces are acting on it: the restoring force exerted by the spring itself, trying to return to its original shape, and the external force applied to stretch the spring. These forces create tension within the spring until a new equilibrium is reached.
The force that causes a spring in a force meter to stretch is the tension or pull applied to the spring by an external force. The spring resists this force by elongating, allowing the force meter to measure the magnitude of the force being applied.
The ratio of force applied to how much the spring streches (or compresses). In the SI, the spring constant would be expressed in Newtons/meter. A larger spring constant means the spring is "stiffer" - more force is required to stretch it a certain amount.
Yes, you can stretch a spring by applying a force to it. When you push or pull on a spring, you are exerting a force that causes the spring to deform and extend. This stretching force is known as tension in the spring.
The spring scale should read the force required to stretch the spring 3.5 cm. This force can be calculated using Hooke's Law, F = kx, where F is the force, k is the spring constant, and x is the distance stretched.
1,500 grams2,500 grams500 grams2,000 grams
Yes, the stretch of a spring is directly proportional to the applied force according to Hooke's Law. This means that as the force applied to a spring increases, the stretch of the spring will also increase in direct proportion to that force until the spring reaches its elastic limit.
It may loose its elastic nature.