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momentum is mass x velocity (p=mv), and velocity is distance divided by time (d/t),

so p=m(d/t)=(70kg)(400m/50s)=560 kgm/s

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Answer #2:

If the questioner actually knew what he was talking about when he posted

the question, then the runner's average momentum is

(70 kg) x (400 miles) x(1,609.344 meters/mile)/(50 seconds) = 9.012 x 105kg-m/sec

We can't help but notice that in the question's frame of reference, the runner is

steaming along at 28,800 miles per hour. This arouses our curiosity, but is not

germaine to the problem or to its solution, and we play the hand we are dealt.

Our math and physics are bullet-proof, and we stand by them.

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βˆ™ 10y ago
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βˆ™ 11y ago

You need to calculate the force to lift the box without acceleration (weight = mg), PLUS the force required for the acceleration (F = ma). By the way, "2 minutes per second" is not a valid acceleration. Acceleration should be in units of (distance / time / time); and you must convert it to meters/second/second (meters/second2) to have consistent units.

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Q: How much force is needed to lift 70kg box with an 2 minutes per seconds acceleration of the box?
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