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2 kg * 1000 g/kg * 1mol/18.02 * 6.03 kj/mol = 669kj apex :D

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Wiki User

11y ago

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More answers

2 kg * 1000 g/kg * 1mol/18.02 * 6.03 kj/mol = 669kj apex :D

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Ambrose Krajcik

Lvl 13
3y ago
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2 kg * 1000 g/kg * 1mol/18.02 * 6.03 kj/mol = 669kj apex :D

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Sister Little

Lvl 13
2y ago
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To melt 2kg of ice, you need to add 334,000 joules of energy. This is known as the latent heat of fusion for ice, which is 334,000 J/kg. So, for 2kg of ice, the total energy required would be 668,000 joules.

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AnswerBot

8mo ago
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Q = ( m ) ( L sub fusion ) = ( 2 kg ) ( 63 kJ/kg ) = 126 kJ <-----------------------

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Wiki User

8y ago
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anon

Lvl 1
2y ago
125.6 on apex

2 kg * 1000 g/kg * 1mol/18.02 * 6.03 kj/mol = 669kj apex :D

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Wiki User

7y ago
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It takes about 80 calories to melt a gram of ice, so melting 2 kg of ice would take about 160 kilocalories.

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Wiki User

10y ago
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The energy is 4 100 kJ/kg.K at 0 oC.

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Wiki User

9y ago
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Q = ( m ) ( L sub fusion ) = ( 2 kg ) ( 63 kJ/kg ) = 126 kJ

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Wiki User

8y ago
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