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At a steady state (when up and running) Watts = Volts x Amps so you just need to solve the equation 75,000 / 400 = ?

However, you add the caveat "starting". If your application involves a motor, for example, the starting current will be higher than the steady state current. One rule of thumb says the starting current may be as high as 6 times the running current. This higher current starts high and then decreases as the motor comes up to speed.

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โˆ™ 14y ago
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โˆ™ 5mo ago

To calculate the current drawn by the motor when starting, you can use the formula: current (A) = power (W) / voltage (V). In this case, the current drawn at the starting is 187.5 A (75000 W / 400 V).

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Q: How much current will draw 75000W 400volt at the starting?
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