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55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
From the balanced chemical equation, 1 mole of C5H12 reacts with 8 moles of O2 to produce 6 moles of H2O. Therefore, when 1 mole of O2 reacts, it will produce 6 moles of H2O.
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
The molecular mass of O2 (oxygen gas) is 32 g/mol. This is calculated by adding the atomic masses of the two oxygen atoms in the molecule (16 g/mol each).
15.99 x 2 g
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
Using the molar mass of oxygen (O2) which is 32 g/mol, you can calculate that you have 3 moles of oxygen gas. Since the ratio of O3 to O2 is 1:2, you would form 1.5 moles of ozone (O3) from 96.0g of O2.
The balanced chemical equation for the reaction is 2Mg + O2 -> 2MgO. This means that 1 mol of Mg will react with 0.5 mol of O2 to form 1 mol of MgO. The molar mass of Mg is 24 g/mol and MgO is 40 g/mol. Therefore, 12 g of Mg will require 3 mol of O2 (3 * 32 g) for complete conversion to MgO.
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
If you start with 4 mol of H2O2 in the reaction 2H2O2 -> 2H2O + O2, you will end up with 2 mol of O2. This is because for every 2 mol of H2O2 that react, 1 mol of O2 is produced.
Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.
Using the molar volume of gas at STP (22.4 L/mol), you can calculate the volume of oxygen gas needed. Calculate the number of moles of Mg (4.03 g Mg / 24.305 g/mol = 0.166 mol Mg). Given the balanced chemical equation (2Mg + O2 → 2MgO), we see that 1 mol of Mg reacts with 1 mol of O2. So, 0.166 mol Mg would require 0.166 mol of O2. Using the molar volume at STP (22.4 L/mol), the volume needed is 0.166 mol * 22.4 L/mol = 3.71 L = 3710 mL.
Type your answer here... 2 × (6.02 × 1023)
1 mol of octane (C8H18) reacts with 25 mol of oxygen (O2) to produce 8 mol of CO2 and 9 mol of H2O. Therefore, 0.74 mol of oxygen can react with 0.0744 mol of octane.
From the balanced chemical equation, 1 mole of C5H12 reacts with 8 moles of O2 to produce 6 moles of H2O. Therefore, when 1 mole of O2 reacts, it will produce 6 moles of H2O.