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Q: How much 1 mol of O2 gas?
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How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?

55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.


The number of moles of h2o formed when 1 mole of o2 reacts with c5h12 in the reaction c5h12 plus 8o2 equals 5co2 plus 6h2o is?

From the balanced chemical equation, 1 mole of C5H12 reacts with 8 moles of O2 to produce 6 moles of H2O. Therefore, when 1 mole of O2 reacts, it will produce 6 moles of H2O.


What is the balanced equation for The total number of grams of CO2 that are produced when 4 grams of C are added to 10.67 grams of O2?

The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.


Calculate the number of atoms of O contained in 16.0 pounds of O?

To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.


What is the molecular mass of O2?

The molecular mass of O2 (oxygen gas) is 32 g/mol. This is calculated by adding the atomic masses of the two oxygen atoms in the molecule (16 g/mol each).

Related questions

How much mass does 1 mol of o2 gas have?

15.99 x 2 g


How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?

55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.


How many moles of ozone O3 could be formed from 96.0g of oxygen gas O2?

Using the molar mass of oxygen (O2) which is 32 g/mol, you can calculate that you have 3 moles of oxygen gas. Since the ratio of O3 to O2 is 1:2, you would form 1.5 moles of ozone (O3) from 96.0g of O2.


What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?

The balanced chemical equation for the reaction is 2Mg + O2 -> 2MgO. This means that 1 mol of Mg will react with 0.5 mol of O2 to form 1 mol of MgO. The molar mass of Mg is 24 g/mol and MgO is 40 g/mol. Therefore, 12 g of Mg will require 3 mol of O2 (3 * 32 g) for complete conversion to MgO.


How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?

By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.


How many moles of oxygen gas O2 needed to react with 4.00 mol of Mg?

Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------


In the reaction 2H2O2-2H2O O2 if you start with 4 mol of H2O2 how many moles of O2 will you end up with?

If you start with 4 mol of H2O2 in the reaction 2H2O2 -> 2H2O + O2, you will end up with 2 mol of O2. This is because for every 2 mol of H2O2 that react, 1 mol of O2 is produced.


How many grams of MgO are produced when 40 grams of 02 react with Mg?

Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.


What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?

Using the molar volume of gas at STP (22.4 L/mol), you can calculate the volume of oxygen gas needed. Calculate the number of moles of Mg (4.03 g Mg / 24.305 g/mol = 0.166 mol Mg). Given the balanced chemical equation (2Mg + O2 → 2MgO), we see that 1 mol of Mg reacts with 1 mol of O2. So, 0.166 mol Mg would require 0.166 mol of O2. Using the molar volume at STP (22.4 L/mol), the volume needed is 0.166 mol * 22.4 L/mol = 3.71 L = 3710 mL.


How many oxygens atoms does 1 mol of O2 gas have?

Type your answer here... 2 × (6.02 × 1023)


How much octane can react with 0.740 of oxygen?

1 mol of octane (C8H18) reacts with 25 mol of oxygen (O2) to produce 8 mol of CO2 and 9 mol of H2O. Therefore, 0.74 mol of oxygen can react with 0.0744 mol of octane.


The number of moles of h2o formed when 1 mole of o2 reacts with c5h12 in the reaction c5h12 plus 8o2 equals 5co2 plus 6h2o is?

From the balanced chemical equation, 1 mole of C5H12 reacts with 8 moles of O2 to produce 6 moles of H2O. Therefore, when 1 mole of O2 reacts, it will produce 6 moles of H2O.