50 grams CaCO3 (1 mole CaCO3/100.09 grams)(6.022 X 1023/1 mole CaCO3)
= 3.0 X 1023 atoms of calcium carbonate
=============================
Chat with our AI personalities
There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
There are three carbon atoms in one molecule of CaCO3 (calcium carbonate).
There are 5 atoms represented in the formula CaCO3: 1 calcium (Ca) atom, 1 carbon (C) atom, and 3 oxygen (O) atoms.
Calcite (CaCO3) contains 5 atoms - one calcium (Ca) atom, one carbon (C) atom, and three oxygen (O) atoms.
There are 10 hydrogen atoms present in 4C2H5OH.
One molecule of CaCO3 contains one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O), for a total of five atoms.