There are 2 oxygen atoms in one molecule of CaCO3. To calculate the number of oxygen atoms in 50 grams of CaCO3, you first need to find the number of moles of CaCO3 using its molar mass. Then, multiply the number of moles by the number of atoms of oxygen per molecule of CaCO3 (2) to find the total number of oxygen atoms.
There are three carbon atoms in one molecule of CaCO3 (calcium carbonate).
There are 5 atoms represented in the formula CaCO3: 1 calcium (Ca) atom, 1 carbon (C) atom, and 3 oxygen (O) atoms.
Calcite (CaCO3) contains 5 atoms - one calcium (Ca) atom, one carbon (C) atom, and three oxygen (O) atoms.
There are 10 hydrogen atoms present in 4C2H5OH.
One molecule of CaCO3 contains one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O), for a total of five atoms.
The formula CaCO3 represents 5 atoms: 1 calcium atom, 1 carbon atom, and 3 oxygen atoms.
Three molecules of calcium carbonate (CaCO3) has nine(9) oxygens. Think of 3CaCO3 = CaCO3 + CaCO3 + CaCO3. Each molecule of CaCO3 has ;- 1 atoms of calcium (Ca) 1 atom of carbon (C) 3 atoms of oxygen (O3 = O + O + O). So if one molecules of CaCO3 has 3 oxygens, then three molecules of CaCO3 has 3 x 3 = 9 oxygens. The answer!!!!!
There are three carbon atoms in one molecule of CaCO3 (calcium carbonate).
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There are 5 atoms represented in the formula CaCO3: 1 calcium (Ca) atom, 1 carbon (C) atom, and 3 oxygen (O) atoms.
There are three oxygen atoms in a molecule of calcium carbonate (CaCO3).
There is 1 Carbon atom in the formula along with 1 calcium and 3 oxygen atoms
The molecule of limestone (calcium carbonate, CaCO3) contain 5 atoms.
0.50 moles CaCO3 (1 mole Ca/1 mole CaCO3)(6.022 X 1023/1 mole Ca)= 3.0 X 1023 atoms of calcium===================
One molecule of CaCO3 is composed of one calcium (Ca) atom, one carbon (C) atom, and three oxygen (O) atoms, for a total of five atoms.
There is one calcium atom in a molecule of calcium carbonate (CaCO3).
Limestone has 5 molecule atoms