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How many moles are present in gram's of silicon Si?
1 g silicon is equal to 0,0356 moles.
How many carbon atoms are present in 1.50 moles of aspirin c9h8o4?
1.50 moles C9H8O4 (9 moles C/1 mole C9H8O4)(6.022 X 1023/1 mole C)= 8.13 X 1024 carbon atoms===================
How many moles present 2.45x1023 molecules of CH2?
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
How many equivalents of are present in a solution that contains 2.75 moles of?
1 mol of hydrogen ion () corresponds to 1 equivalent. Therefore, 2.75 moles of in a solution would contain 2.75 equivalents.
How many liters of n2 gas at stp will be used to produce 8.16 liters of nh3 gas at stp are consumed?
Assuming that you mean the reaction of nitrogen and hydrogen to form ammonia N2 + 3H2 -> 2NH3 1 mole of nitrogen forms 2 moles of ammonia- so 4.08 l of nitrogen will be consumed to form 8.16 moles of ammonia. This assumes both are pretty ideal gases which is a reasonabale approximation.
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many molecules of ammonia NH3 are present in 0.522 moles of ammonia?
There are 3.14 x 10^23 molecules of ammonia in 0.522 moles of ammonia, as 1 mole of a substance contains Avogadro's number (6.02 x 10^23) of molecules.
How many moles of electrons are present in 17 grams of ammonia?
To find the number of moles of electrons in ammonia (NH3), we first need to calculate the number of moles of ammonia using its molar mass. The molar mass of NH3 is 17 g/mol. Therefore, 17 grams of NH3 is equal to 1 mole. Since there are 3 electrons in each molecule of ammonia, there are 6.022 x 10^23 electrons present in 1 mole of NH3.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
How many moles of hydrogen atoms are contained in 3 moles of ammonia?
Since ammonia has a chemical formula of NH3, it contains one mole of nitrogen and three moles of hydrogen per mole of ammonia. Therefore, 3 moles of ammonia contain 3 moles of nitrogen and 9 moles of hydrogen atoms.
0.085g of amonia is to how many moles?
The calculation is: Moles = Mass / Atomic Mass Moles = 0.085 / 17 Moles = 0.005 Atomic mass is 17 because ammonia is NH3, with N = 14, and H = 1. 14 + 1 + 1 + 1 = 17.
How many moles of nitrogen are required to produce 18 mol of ammonia?
Three moles of nitrogen are required to produce 2 moles of ammonia according to the balanced chemical reaction for ammonia synthesis. Therefore, 27 moles of nitrogen are required to produce 18 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
One mole of ammonia (NH3) produces one mole of nitrogen (N2) when it decomposes. Therefore, 3.5 moles of nitrogen would require 3.5 moles of ammonia to produce.
How many moles of nitrogen are required to react with 3.4 moles of hydrogen to form ammonia feterlizer?
The balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia is N2 + 3H2 -> 2NH3. This means that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Therefore, to react with 3.4 moles of hydrogen, you would need 3.4/3 = 1.13 moles of nitrogen.
How many moles of ammonia gas are produced by the reaction of 3 mole of nitrogen gas with excess hydrogen gas N2 H2 ---- NH3?
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
How many moles of sulfur are present in 5 moles of H2So4?
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
To find the grams of ammonia present, first calculate the moles of ammonia in the solution using the molarity formula (moles = molarity x volume). Then, convert moles to grams using the molar mass of ammonia (NH3 is 17.03 g/mol). Therefore, in a 5.0 L 0.050 M solution, there would be 4.26 grams of ammonia present.
