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Al donates 3 electrons per mole to be oxidised.
H2SO4 needs (accepts) 2 electrons per mole when oxidising reactive metallics like Aluminum.
(in the following: units are in brackets)
So 2.5 mole Al reacts with 2.5(molAl) * 3(el's/molAl) / 2(el's/molH2SO4) =
7.5(el's) / 2(el's/molH2SO4) = 3.75 mole H2SO4

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