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How many moles of which reactant will remain if 1.39 moles of N and 3.44 moles of H will react to form ammonia find out how many grams of ammonia can be formed and how many moles of limiting reactant?
3,44 moles H2 react with 1,146 moles NH3. The limiting reactant is hydrogen. O,244 moles N2 remain. 19,5 g NH3 are obtained.
How many grams of H2 are needed to produce 10.06 g of NH3?
The formula reaction for NH3 when using N2 and H2 is: (N2)+3(H2) ---> 2(NH3) Now, first step is to find the moles of the H2 reactant. This is found via (grams of reactant)/(molar mass of reactant). There are 10 grams, and the molar mass of H2 is approximately 2.016. Therefore, the equation should look like: 10/2.016. This yields a value of ~4.9606 moles of H2. Now, you use the molar ratio from the reactant to the product to determine how many moles of product were yielded. According to the reaction, three moles of H2 are required to produces 2 moles of NH3. So, the mole ratio is 2/3. Multiply the number of moles of H2 with the molar ratio to determine the moles of NH3. 4.0606 * 2/3 = 3.3071 moles of NH3. Multiply the number of moles with the molar mass of NH3 (17.0306), and voila! 3.3071 * 17.0306 = 56.3216 grams. Now, if your teacher is feeling like a stickler about significant figures, than that value should be rounded to 56 grams of NH3.
How many moles of hydrigen are present in a 2 grams sample of hydrogen gas?
There are approximately 2 moles of hydrogen gas in a 2 grams sample. This is calculated by dividing the mass of the sample by the molar mass of hydrogen gas, which is approximately 1 g/mol. Thus, 2 grams ÷ 1 g/mol = 2 moles.
18 l of ammonia were produced by the haber process how many liters of hydrogen were used during the reaction the reaction took place at stp 0ºc and 1.0 atm n2 g plus 3 h2 g --2 nh3 g?
According to the balanced chemical equation, 3 moles of hydrogen are required to produce 2 moles of ammonia. As 22.4 liters of any gas at STP is equal to 1 mole, 1 mole of hydrogen gas occupies 22.4 liters. Therefore, to produce 18 liters of ammonia, (18/22.4) x 3 = 2.68 moles of hydrogen were used. This equates to 2.68 x 22.4 = 60.03 liters of hydrogen gas used during the reaction.
How many moles of nitrogen would be needed to completely react with 12 moles of hydrogen according to the balanced equation given below?
N2 + 3H2 -> 2NH3 3 moles hydrogen gas. You should know that because of the formula of ammonia.
How many hydrogen molecules are needed to produce 525 grams of ammonia?
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
How many moles of ammonia are produced from 12.0 moles of hydrogen?
Ammonia is produced from the reaction of hydrogen and nitrogen in a 3:1 ratio. Therefore, 12.0 moles of hydrogen will produce 4.0 moles of ammonia.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
One mole of ammonia (NH3) produces one mole of nitrogen (N2) when it decomposes. Therefore, 3.5 moles of nitrogen would require 3.5 moles of ammonia to produce.
Ammonia gas NH3 can be manufactured by combining hydrogen and nitrogen gases If 28 g of nitrogen and 7 g of hydrogen are available how many grams of ammonia can be produced?
The balanced chemical equation for the formation of ammonia from nitrogen and hydrogen is N2 + 3H2 → 2NH3. From the equation, it can be seen that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Calculate the moles of nitrogen and hydrogen provided, determine the limiting reactant, and then use stoichiometry to find the grams of ammonia that can be produced.
How many moles of ammonia can be produced from 18 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
How many moles of hydrogen are required to produce 18.00 moles of ammonia?
Three moles of hydrogen are required to produce one mole of ammonia according to the balanced chemical equation for the reaction of nitrogen and hydrogen to produce ammonia. Thus, 54 moles of hydrogen are required to produce 18.00 moles of ammonia.
How many moles of nitrogen and hydrogen are needed to get 10 moles of ammonia?
For every mole of ammonia produced, we need one mole of nitrogen and three moles of hydrogen. Therefore, to produce 10 moles of ammonia, we would need: 10 moles of nitrogen 30 moles of hydrogen
How many grams of ammonia NH3 will be prepared when 6.00g of hydrogen H2 has reacted?
The reaction between hydrogen and ammonia to form ammonia is 3H2 + N2 → 2NH3. To find the amount of ammonia produced when 6.00g of hydrogen reacts, first convert the mass of hydrogen to moles using its molar mass. Then, use the mole ratio from the balanced equation to find the moles of ammonia produced, and finally, convert this to grams using the molar mass of ammonia.
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
For the reaction: N2 + 3H2 -> 2NH3, you need 3 moles of hydrogen for every 2 moles of ammonia produced. Therefore, to produce 6.0 moles of ammonia, you would need 9.0 moles of hydrogen.
If an excess of nitrogen is reacted with 3.41 grams of hydrogen how many grams of ammonia can be produced?
To determine the amount of ammonia that can be produced, we need to first find the limiting reactant. Once the limiting reactant is identified, we can calculate the theoretical yield of ammonia using stoichiometry. From the balanced chemical equation for the reaction between nitrogen and hydrogen to form ammonia, we can determine that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Utilize this information to convert the given mass of hydrogen to moles, compare it to the moles of nitrogen present, and calculate the maximum yield of ammonia.
What has more atoms 17.031 grams of ammonia or 72.922 grams of hydrogen chloride?
17.031 grams of ammonia has more atoms because ammonia has a larger molecular weight than hydrogen chloride. Ammonia has a molecular weight of 17 grams/mole and hydrogen chloride has a molecular weight of 36.5 grams/mole, so the same mass of ammonia would contain more moles and therefore more atoms.
Mass of 3 moles of ammonia?
Molar mass of ammonia = (14.01 + 3.03) (Molar mass of nitrogen + 3 times molar mass of hydrogen, as chemical formula of ammonia is NH3). Molar mass= 17.04 Molar mass x moles = mass 17.04 x 3 = 51.12 Mass of 3 moles of ammonia is 51.12g.
