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How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
5.8 grams in 1 liter of water equals how many moles?
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
How many grams of hydrogen are in 25.0g of water?
There are 2.22 grams of hydrogen in 25.0 grams of water.
A sample of 90 g water was decomposed using electrolysis How many liters of hydrogen where produced at STP?
The molar mass of water is 18 g/mol. Since there are 2 hydrogen atoms in each water molecule, the molar mass of hydrogen is 2 g/mol. Therefore, 90 g of water contains 5 moles of water, which means 10 moles of hydrogen were produced. At STP, 1 mole of any gas occupies 22.4 liters, so 10 moles of hydrogen would occupy 224 liters.
18 l of ammonia were produced by the haber process how many liters of hydrogen were used during the reaction the reaction took place at stp 0ºc and 1.0 atm n2 g plus 3 h2 g --2 nh3 g?
According to the balanced chemical equation, 3 moles of hydrogen are required to produce 2 moles of ammonia. As 22.4 liters of any gas at STP is equal to 1 mole, 1 mole of hydrogen gas occupies 22.4 liters. Therefore, to produce 18 liters of ammonia, (18/22.4) x 3 = 2.68 moles of hydrogen were used. This equates to 2.68 x 22.4 = 60.03 liters of hydrogen gas used during the reaction.
How many moles of H are in 2 mol of c8h18?
There are 18 moles of hydrogen atoms in 2 moles of C8H18 because each mole of C8H18 contains 18 hydrogen atoms.
How many moles of ammonia can be produced from 18 moles of hydrogen?
The balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is: 3H2 + N2 -> 2NH3 From the equation, it can be seen that 3 moles of hydrogen react to produce 2 moles of ammonia. Therefore, 18 moles of hydrogen can produce (2/3) x 18 = 12 moles of ammonia.
How many moles of carbon and hydrogen are there in 5 moles of octane?
In 5 moles of octane, C8H18, there are 40 moles of carbon atoms (5 moles octane x 8 carbon atoms) and 90 moles of hydrogen atoms (5 moles octane x 18 hydrogen atoms).
How many moles of hydgrogen are needed to produce 6.0 moles of ammonia?
For the reaction: N2 + 3H2 -> 2NH3, you need 3 moles of hydrogen for every 2 moles of ammonia produced. Therefore, to produce 6.0 moles of ammonia, you would need 9.0 moles of hydrogen.
How many grams of water are produced when 2.5 mil oxygen reacts with hydrogen?
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
How many atoms of H are in 2 mol of c8h18?
To determine the number of hydrogen atoms in 2 mol of C8H18, we first need to calculate the molar mass of C8H18. Carbon has a molar mass of approximately 12 g/mol, and hydrogen has a molar mass of approximately 1 g/mol. Therefore, the molar mass of C8H18 is (812) + (181) = 114 g/mol. Next, we use Avogadro's number (6.022 x 10^23) to calculate the number of molecules in 2 mol of C8H18, which is 2 mol * 6.022 x 10^23 molecules/mol. Since there are 18 hydrogen atoms in each molecule of C8H18, the total number of hydrogen atoms in 2 mol of C8H18 is 2 mol * 6.022 x 10^23 molecules/mol * 18 atoms/molecule = 2.17 x 10^25 hydrogen atoms.
How many moles of water are present 180 grams of water?
To find the number of moles in 180 grams of water, divide the mass by the molar mass of water. The molar mass of water is approximately 18 g/mol (2*1 (hydrogen) + 16 (oxygen)). So, 180g ÷ 18 g/mol = 10 moles of water.
How many grams of water can be prepared from 5moles of hydrogen at standard conditions?
At standard conditions, 1 mole of hydrogen reacts with 0.5 moles of oxygen to form 1 mole of water. Therefore, to form 5 moles of water, you will need 5 moles of hydrogen and 2.5 moles of oxygen. The molar mass of water is approximately 18 g/mol, so 5 moles of water would weigh 90 grams.
How many grams of water are made from complete reaction of 2.2 moles of oxygen gas with hydrogen gas?
The balanced chemical equation for the reaction of hydrogen gas and oxygen gas to form water is 2H₂ + O₂ → 2H₂O. This means that 2 moles of water are produced for every 1 mole of oxygen gas. Therefore, 4.4 moles of water are produced from the reaction of 2.2 moles of oxygen gas. To convert moles of water to grams, you would need to use the molar mass of water, which is approximately 18 grams/mol. So, 4.4 moles of water would weigh approximately 79.2 grams (4.4 moles x 18 grams/mol).
How many grams of hydrogen are needed to produce 30.0 grams of water?
To find the amount of hydrogen needed to produce water, we need to consider the chemical formula of water, which is H2O. This indicates that there are 2 grams of hydrogen for every 18 grams of water. Therefore, 30.0 grams of water would require 3.33 grams of hydrogen (30.0 grams * 2 grams/18 grams).
5.8 grams in 1 liter of water equals how many moles?
To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).
How many grams of hydrogen are in 25.0g of water?
There are 2.22 grams of hydrogen in 25.0 grams of water.
