A 63,60 g sample of carbon is equal to 5,296 moles.
To find the number of moles of carbon monoxide in 36.55 g, you need to use its molar mass. The molar mass of carbon monoxide is 28.01 g/mol. Divide the given mass by the molar mass to find the number of moles: 36.55 g / 28.01 g/mol = 1.30 moles of carbon monoxide.
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
A 63,60 g sample of carbon is equal to 5,296 moles.
To find the number of moles of carbon monoxide in 36.55 g, you need to use its molar mass. The molar mass of carbon monoxide is 28.01 g/mol. Divide the given mass by the molar mass to find the number of moles: 36.55 g / 28.01 g/mol = 1.30 moles of carbon monoxide.
1,4 moles carbon monoxide are produced.
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
The answer is 7,829.10 ex.23 atoms.
3
To calculate the number of atoms in 63.5 g of carbon monoxide, first determine the number of moles of carbon monoxide using its molar mass (28.01 g/mol). Then, use Avogadro's number (6.022 x 10^23) to convert moles to atoms. A single molecule of carbon monoxide consists of 1 carbon atom and 1 oxygen atom.
Each molecule of C6H6 contains 6 carbon atoms, so when 1 mole of C6H6 decomposes, 6 moles of carbon atoms are obtained. Therefore, in a 1.68 mole sample of C6H6, 6 × 1.68 = 10.08 moles of carbon atoms can be obtained from the decomposition.
The answer is 10 moles of carbon monoxide.2 C + O2 = 2 CO
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
In order to find number of molecules from moles, you must multiply moles by avagadro's number, which is 6.02*10^23.
80,0 moles of CO2is equal to 3 520,8 g.