Wiki User
∙ 9y agoYou can use the equationPV=nRT. So there are 0.12231 moles inthat volume.
Wiki User
∙ 8y agoThe answer is 0,125 moles.
0.125 moles
Air is a mixture.
This is another calculation. there are 0.123 moles inn this volume.
The answer is 97,66 moles.
0.125 moles
The answer is 0,125 moles.
0.125 moles
Air is a mixture.
This is another calculation. there are 0.123 moles inn this volume.
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
3 (L) / 22.4 (L/mol) = 0.13 mol of any gas at STPapex- 0.125 moles
Using the ideal gas law (PV = nRT), we can calculate the number of moles of air in the container. Rearranging the formula to solve for n (moles), we get n = (PV) / (RT). Plugging in the values (P = 1 atm, V = 3 L, R = 0.0821 Latm/molK, T = 293 K) and solving for n gives us approximately 0.12 moles of air.
The answer is 97,66 moles.
To determine the number of moles of air in the container, we need to use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. Rearranging the equation to solve for n, we get n = PV / RT. Plugging in the values (P = 1 atm, V = 3 L, T = 293 K, R = 0.0821 L.atm/mol.K), we find n = (1 atm * 3 L) / (0.0821 L.atm/mol.K * 293 K) = 0.123 moles.
PV = nRT so --- P = nRT/V = 1.09(8.314)(293)/(2.00) = 1327.62109 kPa
There are approximately 1.8 x 10^24 molecules in 3 moles of carbon dioxide. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles.