V1= [V2 * M2] / M1 = [5.00 (L) * 3.00 (mol/L)] / 12.6 (mol/L) = 15.0/12.6 = 1.19 L
So carefully add a volume of 1.19 L of 12.6M HCl, as accurately as possible to about 3.5 L Water in a 5.00 L calibrated glass cylinder and fill this up to the 5L mark after mixing.
Wiki User
∙ 12y agoWiki User
∙ 12y agoThere are 8.33 * 10^(-3) moles of H+ in your solution
pH = -log [H+]
[H+] = 10^(-pH)
[H+] = 0.001 mol/L
n = C / V
n = 0.001 / 0.120
n = 0.008333... mol
Wiki User
∙ 15y ago12 M = 12 moles HCl per 1 liter of solution...so 12 moles/ 1 liter = 3 moles/ X liters. X = 0.25 liters of 250mL
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∙ 10y ago>(0.600 M)(300mL) = 180
>180/12.0= 15.0mL
Hope this helps. =))
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∙ 11y ago3/12 = 0.25 molar or 0.25 M
Wiki User
∙ 7y agoThe answer is 36 moles HCl.
Wiki User
∙ 13y ago0.25 M
Wiki User
∙ 13y ago0.25M
120 grams of calcium contain 2,994 moles.
120 g calcium is equal to 3 moles.
To calculate normality, we need to know the equivalent weight of H3PO4. The equivalent weight of H3PO4 is 98 g/mol. First, calculate the number of moles of H3PO4: 275g / 98 g/mol = 2.81 mol Then, calculate the Normality: Normality = (moles of solute) / (volume of solution in L) = 2.81 mol / 120 L = 0.0235 N.
120
120, 000 Kilo means thousand so....120 thousand.
120 grams of calcium contain 2,994 moles.
120 g calcium is equal to 3 moles.
0,288 moles
i think its 120 (40x3)
To find the number of moles in 120 grams of sodium, divide the given mass by the molar mass of sodium. The molar mass of sodium is approximately 23 grams per mole. Therefore, 120 grams of sodium is equal to 120/23 ≈ 5.22 moles of sodium.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
0.67 moles of C6H12O6
To convert grams of a substance to moles, you need to use the molar mass. The molar mass of chlorine gas (Cl2) is approximately 70.9 g/mol. So, to convert 120g of chlorine gas to moles, you would divide 120g by 70.9 g/mol, giving you approximately 1.69 moles.
n = 817 g x (1 mol / 120 g) = 6.81 mol
To find the number of moles in 120 grams of NaOH, first calculate the molar mass of NaOH (sodium: 22.99 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol) which is 40 g/mol. Then, divide the given mass (120 g) by the molar mass to get the number of moles: 120 g / 40 g/mol = 3 moles of NaOH.
120
To find the molarity, first calculate the number of moles of calcium nitrite using its molar mass. Then, divide the number of moles by the volume of the solution in liters (240 mL = 0.24 L) to get the molarity.