800 g oxygen are needed.
0.035mol. Apply to PV=nRT
At STP, assuming petrol is octane with a density of .8 ---- 1 L x .8 = 800 grams --- octane has a molar mass of 116 g/mole --- 800 g / 116 = 7 moles 1 mole of vapour (gas) at STP occupies 22.4 L 22.4 x 7 = 156.8 Liters
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
There are 800,000 metres in 800 kilometres.
In 0.800 moles of MgO, there are the same number of oxygen atoms as there are in 0.800 moles of O atoms. One mole of MgO contains one mole of oxygen atoms, which is equivalent to 6.022 x 10^23 oxygen atoms.
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.
800 g oxygen are needed.
The molar ratio of oxygen to dihydrogen sulfide in the reaction is 3:1. First, find the number of moles of dihydrogen sulfide by dividing its mass by its molar mass. Then, use the mole ratio to calculate the moles of oxygen needed. Finally, convert the moles of oxygen to grams.
0.035mol. Apply to PV=nRT
At STP, assuming petrol is octane with a density of .8 ---- 1 L x .8 = 800 grams --- octane has a molar mass of 116 g/mole --- 800 g / 116 = 7 moles 1 mole of vapour (gas) at STP occupies 22.4 L 22.4 x 7 = 156.8 Liters
For this you need the atomic mass of Na. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.1 moles Na × (23.0 grams) = 48.3 grams Na
A pioneer in Agricultural science, Luther Burbank produced over 800 varieties of plants using genetic engineering. He developed the spineless cactus and the plumcot.
How many 25ยข is in $800
There are 800 millions in 800 million.
800mL equals 80cL
It goes in 800 times.