The answer is 0,615 moles.
10 moles of sodium chloride have 584,397 g.
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol β 0.483 moles of Al2O3.
1 g silicon is equal to 0,0356 moles.
3,42 moles of phosphorus trichloride have 469,6686 g.
The answer is 0,615 moles.
The answer is 1.35 moles.425 g of UF4 would be 1.35 moles.
10 moles of sodium chloride have 584,397 g.
To find the number of moles, we need to use the molar mass of Al2O3, which is 101.96 g/mol. Divide the given mass (49.3 g) by the molar mass to get the number of moles of Al2O3 present. 49.3 g / 101.96 g/mol β 0.483 moles of Al2O3.
To determine the number of moles of aluminum present, we need to first determine the molar mass of aluminum, which is approximately 26.98 g/mol. We can then use the formula: moles = mass / molar mass. Plugging in the values, we get moles = 15 g / 26.98 g/mol β 0.56 moles of aluminum.
1 g silicon is equal to 0,0356 moles.
3,42 moles of phosphorus trichloride have 469,6686 g.
The answer is 7,44.10e-6 mol.
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
To determine how many moles of octane are present in 16.0 g, you would divide the mass of octane by its molar mass. The molar mass of octane (C8H18) is approximately 114.23 g/mol. Therefore, 16.0 g Γ· 114.23 g/mol = 0.14 moles of octane.
1 g of ammonia (NH3) is equal to 0,059 mol.
The answer is 24,92 g nitrogen.