Wiki User
∙ 9y agoThis value is 0,06 moles.
Wiki User
∙ 8y agoThe solution is 0,25 M.
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
If the hydrate contains 45% water, then one mole of the hydrate will contain 0.45 moles of water.
First, calculate the moles of water: 175g / 18.0116 g/mol = 9.721 moles. The total moles in the solution is the sum of water and phosphoric acid (H3PO4) moles. Next, calculate the mole fraction of H3PO4: moles of H3PO4 / total moles in the solution. This will give you the mole fraction of phosphoric acid in the solution.
3 moles in 1 liter = 3 M
The solution is 0,25 M.
To find the mole fraction of ethanol, you first calculate the total moles of the solution, which is 3.00 + 5.00 = 8.00 moles. Then, you divide the moles of ethanol by the total moles of the solution: 3.00 moles / 8.00 moles = 0.375. So, the mole fraction of ethanol in the solution is 0.375.
To calculate the mole fraction of water in the solution, we first need to determine the moles of water and ethanol present. Given that the solution is 57% water by mass, we can assume the remaining 43% is ethanol. From there, we can convert the mass percentages to moles using the molar masses of water and ethanol, and finally, calculate the mole fraction of water by dividing the moles of water by the total moles of the solution.
The definition of 0.175 m KF is that 1 kg of water contains 0.175 moles of KF. Thus, 347 g of water is equivalent to 0.347 kg, and to find moles of KF, you calculate as follows:0.175 moles/Kg x 0.347 kg = 0.0607 moles of KF are present (3 significant figures).
The molarity of the solution can be calculated by dividing the moles of solute by the volume of solution in liters. In this case, 2 moles of NaOH in 1620 mL (1.62 L) of water gives a molarity of approximately 1.23 M.
In one mole of this solution, there are seven moles of H2O.
The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. In this case, the molarity of the solution is 3 moles / 5 L = 0.6 M.
The molarity of a solution is calculated as moles of solute divided by liters of solution. In this case, 6 moles of NaCl dissolved in 2 L of water would give a molarity of 3 M (6 moles / 2 L).
The molarity of the salt solution can be calculated by dividing the number of moles of solute (salt) by the volume of solution in liters. In this case, the molarity would be 10 moles / 20 liters = 0.5 moles per liter (M).
If the hydrate contains 45% water, then one mole of the hydrate will contain 0.45 moles of water.
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kg. In this case, the moles of NaCl is 3.0 and the mass of water is 1.5 kg. Therefore, the molality of the solution is 2.0 mol/kg.
First, calculate the moles of water: 175g / 18.0116 g/mol = 9.721 moles. The total moles in the solution is the sum of water and phosphoric acid (H3PO4) moles. Next, calculate the mole fraction of H3PO4: moles of H3PO4 / total moles in the solution. This will give you the mole fraction of phosphoric acid in the solution.