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The "8.00 M Ba(OH)2" means 1 L of that solution contains 8.00 mol Ba(OH)2.

125 mL x 1 L x 8.00 mol Ba(OH)2 = 1.00 mol Ba(OH)2

...........1000 mL ........ 1 L

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13y ago
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2w ago

To calculate the number of moles of Ba(OH)2 present in 125 mL of 8.00 M Ba(OH)2 solution, you can use the formula: moles = molarity x volume (in liters). First, convert 125 mL to liters (0.125 L), then multiply 8.00 M by 0.125 L to get 1.00 moles of Ba(OH)2.

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Q: How many moles of BaOH2 are present in 125 mL of 8.00 M BaOH2?
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