To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
The answer is 3,375 moles oxygen.
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
To determine the number of moles of N2 in 50g, you first need to find the molar mass of N2 (28.02 g/mol). Then, you divide the given mass (50g) by the molar mass to get the number of moles. In this case, 50g / 28.02 g/mol ≈ 1.79 moles of N2.
To determine the number of moles in 50g of NaCl, you first need to find the molar mass of NaCl, which is approximately 58.44 g/mol. Then, you divide the given mass by the molar mass to find the number of moles. So, 50g of NaCl represents approximately 0.855 moles (50g / 58.44 g/mol = 0.855 mol).
0.49038225061051505
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
A 50g sample of H2O contains approximately 2.78 x 10^24 molecules of water. This is calculated by first converting the mass to moles, then using Avogadro's number to determine the number of molecules present in that many moles of water.
The answer is 3,375 moles oxygen.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O2) is 4 Al + 3 O2 → 2 Al2O3. This means that 3 moles of O2 react with 4 moles of Al. Therefore, to react with 5 moles of Al, you would need (5 moles Al) x (3 moles O2 / 4 moles Al) = 3.75 moles of O2.
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
There are approximately 0.21 cups in 50g.