3,2x10e22 atoms of sulfur is equivalent to 0,053 moles.
6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
800 g oxygen are needed.
To find the number of moles in 5 grams of sulfur, you need to divide the mass of the sample by the molar mass of sulfur. The molar mass of sulfur is approximately 32.06 g/mol. Therefore, 5 grams of sulfur would be equal to 0.156 moles.
3,2x10e22 atoms of sulfur is equivalent to 0,053 moles.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
2,6 moles of sulfur are equal to 83,356 g.
In CS2, there is 1 sulfur atom per molecule. Therefore, 4.2 moles of CS2 would contain 4.2 moles of sulfur atoms.
6,5 grams of sulfur S are equal to 0,203 moles.
6,35 moles of S contain 38,24059444195.10e23 sulfur atoms.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
To find the number of moles in 112g of sulfur, you need to divide the given mass by the molar mass of sulfur, which is approximately 32.06 g/mol. Therefore, 112g of sulfur is equal to 3.49 moles.
In sulfur trioxide (SO3), there are 1 sulfur atom and 3 oxygen atoms. Therefore, in 2.00 moles of SO3, there would be 2.00 moles of sulfur atoms and 6.00 moles of oxygen atoms.
To determine the number of moles of sulfur in 53.7 grams, you first need to calculate the molar mass of sulfur, which is approximately 32.06 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.7 grams of sulfur is equivalent to about 1.68 moles.
Mass = Moles x Ar = 12.5 x 24 = 300g