300 g sulfur is equivalent to 9,357 moles.
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
300 moles of nitrogen equals 8404,2 g.The density of nitrogen at 20 oc and 1 at is 1,251 g/cm3.8404,2 g nitrogen equals 6 718 L.1 kL = 1 000 LSo the volume of 300 moles N2 is 6,718 kL.
This is very easy. you need 9.752l for that.
Using the ideal gas law, you can calculate the number of moles of gas using the formula PV = nRT. First, convert the initial temperature of 67 degrees Celsius to Kelvin by adding 273 to it, which gives 340 K. Then apply the formula with the initial conditions to solve for n, which would be approximately 11 moles of gas.
300 g sulfur is equivalent to 9,357 moles.
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
To find the number of moles, use the formula: moles = Molarity (M) x Volume (L). First, convert 300 ml to liters by dividing by 1000: 300 ml / 1000 = 0.3 L. Then, calculate moles = 1.5 M x 0.3 L = 0.45 moles. Therefore, there would be 0.45 moles in 300 ml of a 1.5 M solution.
Generally speaking about 300 gallons per acre.
To find the moles of NaOH needed, use the formula: moles = concentration (molarity) x volume (liters). First, convert 300 mL to liters (0.3 L). Then, calculate: moles = 0.2 mol/L x 0.3 L = 0.06 moles. Therefore, 0.06 moles of NaOH are needed to prepare 300 mL of a 0.2 M solution.
To calculate the moles of potassium hydroxide needed, use the formula: moles = molarity * volume (in liters). First, convert 300 mL to liters (0.3 L). Then, moles = 0.250 mol/L * 0.3 L = 0.075 moles of potassium hydroxide needed to prepare the solution.
To determine the number of moles in 300 grams of calcium sulfide, first calculate the molar mass of calcium sulfide (CaS). The molar mass of CaS is 40.08 g/mol (for calcium) + 32.06 g/mol (for sulfur), which equals 72.14 g/mol. Next, divide the given mass by the molar mass to find the number of moles: 300 g / 72.14 g/mol ≈ 4.16 moles.
Molarity = moles of solute/Liters of solution ( 300 ml = 0.300 Liters ) For our purposes, Moles of solute = Liters of solution * Molarity Moles NaCl = 0.300 Liters * 0.15 M = 0.05 moles NaCl =============
26.9 - 27.4
To calculate the molarity, you first need to convert the mass of NaCl to moles. The molar mass of NaCl is 58.44 g/mol. Therefore, 300 grams of NaCl is equal to 300/58.44 = 5.13 moles. Next, divide the moles of NaCl by the volume of the solution in liters (3000 L) to get the molarity, which is 5.13 moles / 3000 L = 0.00171 M.
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
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