answersLogoWhite

0


Best Answer

1,8 grams of fluorine is equivalent to 0,0947 moles.

User Avatar

Wiki User

8y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How many moles are there in 1.8 grams of fluorine?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

How many grams are in 1.5 moles of water?

There are approximately 27 grams in 1.5 moles of water.


How many moles in 60 grams of H2O?

There are approximately 3.33 moles of H2O in 60 grams.


How many moles of water are present in 48 grams?

To find the number of moles in 48 grams of water, we first need to calculate the molar mass of water (H2O), which is approximately 18 grams/mol (1 mol of H2O = 18 grams). Then, we divide the given mass (48 grams) by the molar mass to get the number of moles. In this case, 48 grams / 18 grams/mol ≈ 2.67 moles of water.


How many grams of water are produced when 2.5 mil oxygen reacts with hydrogen?

When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.


How many moles of water in 1.0 grams of water?

1/18 = 0.0556


How many moles of water are there in 1000 grams of water?

Water has a molecuar mass of 18. This means it weights 18g per a mole. The molecular formula for water is H20. Your answer for how many moles in 1000 grams of water is 55.5084351.


5.8 grams in 1 liter of water equals how many moles?

To convert grams to moles, divide the mass in grams by the molar mass of the substance. The molar mass of water is approximately 18 g/mol (1 g/mol for hydrogen and 16 g/mol for oxygen). So, 5.8 grams of water in 1 liter would be approximately 0.32 moles (5.8 g / 18 g/mol).


How many moles are in 1 gram of H2O?

There is approximately 0.055 moles of water (H2O) in 1 gram. This can be calculated by dividing the given mass (1 gram) by the molar mass of water (18 grams/mol).


When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?

To calculate the grams of water formed, we first need to determine the moles of nitrogen and oxygen produced. Using the given data, we find that 14 grams of nitrogen is equivalent to 1 mole and 8 grams of oxygen is also equivalent to 0.5 moles. In the explosion, these moles of nitrogen and oxygen will combine with hydrogen to form water. Since the molar ratio of hydrogen to nitrogen and oxygen is 2:1, the moles of water produced will be 1 mole (from nitrogen) + 0.5 moles (from oxygen) = 1.5 moles. Finally, converting moles to grams, 1.5 moles of water is equal to 18 grams. Thus, 18 grams of water would form during the explosion.


How many moles of water molecules H2O are present in a 27 gram sample of water?

There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).


How many grams of hydrogen are needed to produce 30.0 grams of water?

To find the amount of hydrogen needed to produce water, we need to consider the chemical formula of water, which is H2O. This indicates that there are 2 grams of hydrogen for every 18 grams of water. Therefore, 30.0 grams of water would require 3.33 grams of hydrogen (30.0 grams * 2 grams/18 grams).


How many moles are present in 500.00 g of H2O?

For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams500.0 grams H2O / (18.0 grams) = 27.8 moles H2O