Well, it depends on what measurements you are using for the MW of H. Say you refer to a mole as 6.022x1023 and H is 1.008. This means that one mole of H weighs 1.008 g. So you use this conversion. Probally a homework problem so i think you can use a calculator. 5.00g H X 1 mol H ---- 1 X 1.008g H
Anyone feel free to correct me!
There are approximately 2 moles of hydrogen gas in a 2 grams sample. This is calculated by dividing the mass of the sample by the molar mass of hydrogen gas, which is approximately 1 g/mol. Thus, 2 grams รท 1 g/mol = 2 moles.
The answer is 0,2675 moles.
750 L hydrogen gas at 0 0C and 1 at is equal to 33,44 moles.
The answer is 13,89 moles.
Ideal gas equation. PV = nRT ===============
To find the number of moles of hydrogen gas, we first need to convert the mass of hydrogen gas from grams to moles using the molar mass of hydrogen gas (2 g/mol). 5.04 grams of hydrogen gas is equal to 5.04 g / 2 g/mol = 2.52 moles of hydrogen gas.
There are approximately 2 moles of hydrogen gas in a 2 grams sample. This is calculated by dividing the mass of the sample by the molar mass of hydrogen gas, which is approximately 1 g/mol. Thus, 2 grams รท 1 g/mol = 2 moles.
You can determine the moles of HCl formed by using a balanced chemical equation for the reaction between hydrogen gas and chlorine. Calculate the stoichiometric ratio of hydrogen to HCl in the balanced equation to determine the moles of HCl formed from the given moles of hydrogen gas.
The answer is 0,2675 moles.
To find the number of moles of hydrogen gas, we first need to calculate the number of moles of chlorine gas using the ideal gas law formula (PV = nRT). Once we have the moles of chlorine gas, we can determine the moles of hydrogen gas needed for the reaction. In this case, the stoichiometry of the reaction states that 1 mole of chlorine gas reacts with 1 mole of hydrogen gas, so the required moles of hydrogen gas will be equal to the moles of chlorine gas.
There are approximately 4.48 moles of hydrogen gas in a gallon at standard temperature and pressure (STP).
750 L hydrogen gas at 0 0C and 1 at is equal to 33,44 moles.
The answer is 13,89 moles.
The number of moles of helium is 0,32.
To find the number of moles in 18.0 grams of hydrogen gas, you need to divide the given mass by the molar mass of hydrogen gas. The molar mass of hydrogen gas (H2) is about 2.016 grams/mol. So, 18.0 grams / 2.016 grams/mol โ 8.93 moles of hydrogen gas.
To find the volume of hydrogen gas produced, we first need to convert the mass of baking soda (645g) to moles. Then, using the balanced chemical equation for the reaction, we can determine the moles of hydrogen gas produced. Finally, using the ideal gas law at STP, we can convert the moles of hydrogen gas to liters.
For the complete reaction of hydrogen gas ((H_2)), the balanced chemical equation is: (2H_2 + O_2 \rightarrow 2H_2O) This means that 2 moles of hydrogen gas react to produce 2 moles of water. Therefore, 1.4 moles of hydrogen gas will produce 1.4 moles of water.