how many moles are in 95.0 gram of octane?
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
The answer is 0,111 moles.
85.2 gram LiF sample is equivalent to 3,28 moles.
27g
how many moles are in 95.0 gram of octane?
No moles of BaCO3 are found in any amount of Li.
The answer is 3 moles.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
To find the number of moles of Li atoms in 10.56g of Li, you need to divide the given mass by the molar mass of Li (6.94 g/mol). 10.56g / 6.94 g/mol = 1.52 moles of Li atoms.
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
The answer is 0,111 moles.
85.2 gram LiF sample is equivalent to 3,28 moles.
The balanced chemical equation for the reaction is 3Li + H3PO4 -> Li3PO4 + 3H2. The mole ratio is 1:1 between Li and H3PO4. Therefore, 4 moles of H3PO4 will react with 4 moles of Li.
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
There are 1.81 x 10^24 atoms in 3.00 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
3.0 moles of H2O have 54 g.