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how many moles are in 95.0 gram of octane?
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
The answer is 0,111 moles.
85.2 gram LiF sample is equivalent to 3,28 moles.
27g
how many moles are in 95.0 gram of octane?
No moles of BaCO3 are found in any amount of Li.
85 moles Li x 6.02x10^23 atoms/mole Li = 5.17x10^25 atoms of Li
The answer is 3 moles.
To find the number of moles of Li atoms in 10.56g of Li, you need to divide the given mass by the molar mass of Li (6.94 g/mol). 10.56g / 6.94 g/mol = 1.52 moles of Li atoms.
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
The answer is 0,111 moles.
The balanced chemical equation for the reaction is 3Li + H3PO4 -> Li3PO4 + 3H2. The mole ratio is 1:1 between Li and H3PO4. Therefore, 4 moles of H3PO4 will react with 4 moles of Li.
85.2 gram LiF sample is equivalent to 3,28 moles.
1 mole of Li₂O contains 2 moles of lithium (Li) atoms and 1 mole of oxygen (O) atoms. Therefore, in 1 mole of Li₂O, there are a total of 3 moles of atoms.
There are 1.81 x 10^24 atoms in 3.00 moles of lithium (Li). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
From the periodic table, lithium has an atomic weight of 6.941. The molar mass of an element is the atomic weight in grams. Therefore, 1 mole Li = 6.941g Li Therefore, moles Li = 15g Li X 1 mole Li/6.941g Li = 2.2 moles Li