There are 18.9 moles in 225.8 mg. This is a math problem.
The answer is 0,615 moles.
To find the number of moles in 1.346g of Mg, you need to divide the mass by the molar mass of Mg (24.305 g/mol). 1.346g Mg / 24.305 g/mol = 0.055 moles Mg
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
The number of moles in 432 g Mg (OH)2 is 7,407.
There are 18.9 moles in 225.8 mg. This is a math problem.
The answer is 0,615 moles.
To find the number of moles in 1.346g of Mg, you need to divide the mass by the molar mass of Mg (24.305 g/mol). 1.346g Mg / 24.305 g/mol = 0.055 moles Mg
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
The number of moles in 432 g Mg (OH)2 is 7,407.
32,5 g magnesium is equal to 1,337 mol.
There are 2.47 moles of Mg atoms in 100 g of Mg. This is calculated by dividing the given mass by the molar mass of Mg (24.305 g/mol) to get the number of moles.
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
3.03
To find the amount of water needed, we first calculate the molar mass of Mg(OH)2. Mg has a molar mass of 24.31 g/mol, O has 16.00 g/mol, and H has 1.01 g/mol. So, the molar mass of Mg(OH)2 is 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol. To produce 150 g of Mg(OH)2, we need 150 g / 58.33 g/mol = 2.57 moles of Mg(OH)2. Since there are 2 moles of H2O per 1 mole of Mg(OH)2, we need 2.57 moles x 2 = 5.14 moles of H2O. Finally, converting moles to grams, we get 5.14 moles x 18.02 g/mol = 92.54 g of H2O required.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.