0
14,84 g magnesium are equivalent to 0,61 moles.
Wiki User
∙ 7y ago
Add your answer:
Earn +20 pts
How many moles are in 225.8 g of Mg?
There are 18.9 moles in 225.8 mg. This is a math problem.
How many moles of Mg are present in 14.95 g?
The answer is 0,615 moles.
How many moles is 1.346g of Mg?
To find the number of moles in 1.346g of Mg, you need to divide the mass by the molar mass of Mg (24.305 g/mol). 1.346g Mg / 24.305 g/mol = 0.055 moles Mg
How many moles are in 1.2 mg of oxygen?
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
What is the number of moles in 432 g Mg (OH)2?
The number of moles in 432 g Mg (OH)2 is 7,407.
How many moles are in 225.8 g of Mg?
There are 18.9 moles in 225.8 mg. This is a math problem.
How many moles of Mg are present in 14.95 g?
The answer is 0,615 moles.
How many moles is 1.346g of Mg?
To find the number of moles in 1.346g of Mg, you need to divide the mass by the molar mass of Mg (24.305 g/mol). 1.346g Mg / 24.305 g/mol = 0.055 moles Mg
How many moles are in 1.2 mg of oxygen?
The molar mass of oxygen is 32 g.1,2 mg oxygen is equal to 0,0000375 moles.
What is the number of moles in 432 g Mg (OH)2?
The number of moles in 432 g Mg (OH)2 is 7,407.
HOW MANY moles of mg atom are there in 100 gm of mg?
There are 2.47 moles of Mg atoms in 100 g of Mg. This is calculated by dividing the given mass by the molar mass of Mg (24.305 g/mol) to get the number of moles.
How many moles are represented by 32.50 g Mg?
32,5 g magnesium is equal to 1,337 mol.
How many moles of sodium borohydride are used in 100 mg?
To calculate the number of moles of sodium borohydride in 100 mg, you need to know the molar mass of the compound, which is 37.83 g/mol. First, convert 100 mg to grams (0.1 g), then divide by the molar mass to get the number of moles, which is approximately 0.0026 moles.
How many moles of Mg3N2 would be produced when 180.0 g of Mg reacts with 85.0 g of N2?
3.03
How many grams of H2O are needed to produce 150 g of Mg(OH)2?
To find the amount of water needed, we first calculate the molar mass of Mg(OH)2. Mg has a molar mass of 24.31 g/mol, O has 16.00 g/mol, and H has 1.01 g/mol. So, the molar mass of Mg(OH)2 is 24.31 + 2(16.00) + 2(1.01) = 58.33 g/mol. To produce 150 g of Mg(OH)2, we need 150 g / 58.33 g/mol = 2.57 moles of Mg(OH)2. Since there are 2 moles of H2O per 1 mole of Mg(OH)2, we need 2.57 moles x 2 = 5.14 moles of H2O. Finally, converting moles to grams, we get 5.14 moles x 18.02 g/mol = 92.54 g of H2O required.
Which equation shows how to calculate how many grams(g) of Mg(OH)2 would be produced from 4 mol KOH. The balanced reaction is mgcl2 plus 2koh mg(oh)2 plus 2kcl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
