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How many milliliters of 0.305M NaOH would be required to titrate a 5.00mL solution of 0.616M HBr?
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
How many grams HBr are required to produce 150g AlBr3 in the equation 2Al plus 6HBr producing 2AlBr3 and 3H2?
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
What is the chemical formula for Dextromethorphan HBr?
The chemical formula for Dextromethorphan Hydrobromide (HBr) is C18H25NO·HBr.
How many grams in 4.23 m mol of HBr?
The answer is 0,3422 grams.
Give examples of three different heteronuclear diatomic molecules using hydrogen and atoms from only group 7 of the periodic table?
HCl HBr HF
How many moles are present in 1.21 molecules of HBr?
To find the number of moles in 1.21 molecules of HBr, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Thus, 1.21 molecules of HBr is approximately 2.01 x 10^-24 moles.
How many moles are in 186 grams of HBr?
To find the number of moles in 186 grams of HBr, you need to divide the given mass by the molar mass of HBr. The molar mass of HBr is approximately 80.91 g/mol. So, 186 grams of HBr is equal to 2.30 moles.
How many moles are in 135 g of hydrobromic acid?
In the English language hydrobromic acid is the solution of HBr in water; the name of the acid HBr is hydrogen bromide. 135 g HBr are equivalent to 1,67 moles.
How many grams of solid sodium hydroxide would need to be added to completely neutralize 35.0 mL of 1.45 M HBr?
To determine the amount of solid sodium hydroxide needed to neutralize HBr, first calculate the moles of HBr present in 35.0 mL of 1.45 M solution. Then, since the reaction is 1:1 between HBr and NaOH, the moles of NaOH needed would be the same as the moles of HBr. Finally, use the molar mass of NaOH to convert moles to grams.
How many kilojoules are associated with the formation of 2 moles of HBr?
The standard enthalpy of formation of HBr is -36.3 kJ/mol. For 2 moles of HBr, the total energy associated with the formation would be: -36.3 kJ/mol * 2 mol = -72.6 kJ.
What is the concentration of a HBr solution in 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The moles of KOH in the titrant solution can be calculated as 15.0 mL x 0.25 mol/L = 3.75 mmol. Since HBr and KOH react in a 1:1 ratio, the number of moles of HBr in the original solution is also 3.75 mmol. Given the volume of the original HBr solution is 12.0 mL, the concentration would be 3.75 mmol / 12.0 mL = 0.3125 M.
How many milliliters of 0.305M NaOH would be required to titrate a 5.00mL solution of 0.616M HBr?
Since NaOH and HBr react in a 1:1 ratio, the moles of NaOH needed to titrate HBr can be calculated. Moles of NaOH = moles of HBr. Next, use the concentration and volume of HBr to find the moles present. Finally, use the concentration of NaOH to calculate the volume needed. In this case, approximately 2.41 mL of 0.305M NaOH would be needed.
What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
How many kilo-joules are associated with the formation of 2 moles of HBr(g)?
The standard enthalpy of formation of HBr(g) is -36.2 kJ/mol. For 2 moles of HBr(g), the total energy associated with its formation would be 2 * -36.2 kJ/mol = -72.4 kJ.
How many grams are in 5.00x10^24 molecules of lithium hydroxide?
A mole is the quantity of any molecule, atom, etc that has the same number of ... If I have 6.022×1023 H2 molecules, I have a mass of 2 gram of hydrogen molecules. ... How many moles are present in 1.21 X 10^24 molecules of HBr? ... How do you convert the amount of atoms in each battery to moles of lithium atoms?
A 25.00 mL sample of HBr is titrated with 0.150 M standardized sodium hydoxide solution the endpoint was reached when 18.80 mL of titrant had been added calculate the molar concentration of the HBr?
Using the balanced chemical equation for the reaction between HBr and NaOH (1:1 ratio), we can determine the moles of NaOH used. From the volume of NaOH used, we can then calculate the moles of HBr present in the sample. Finally, dividing moles of HBr by the initial volume of the sample (in liters) gives the molar concentration of HBr.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
