The amount of light output will depend entirely on the construction of the bulb.
The wattage is only a measure of how much power goes into it. Some energy is given off as heat instead of light, depending on the efficiency.
It is best to refer to the manufacturers data sheet (if available), where light measurements may have been tabulated.
Incandescent Watts...... . ..CFL Watt range... . . ... .. Lumen Range 406075100150 8 - 1013 - 1818 - 2223 - 2834 - 42 450890121017502780
A 100-watt electric bulb consumes 200 watt-hours of energy in two hours (100 watts x 2 hours = 200 watt-hours).
If you turn a 60 watt light bulb on and off, it will still consume 60 watts when it is turned on. The act of turning it off does not reduce its power consumption when it is on. However, when the light bulb is turned off, it consumes no power.
To calculate the amperage, you can use Ohm's Law formula: Amperage (A) = Power (W) / Voltage (V). In this case, for a 5 watt bulb at 12 volts, the amperage drawn would be 0.42 amps (5W / 12V = 0.42A).
A 200W light bulb will use 0.2 kWh (kilowatt-hour) of electricity per hour of operation. If the bulb is on for 5 hours, it would consume 1 kWh.
Typically power leds operate as 1-2 watt units. 50 watt is a little excessive for a single led: it would have to be an array. The light output that can be achieved in normal use appears to range from 80-120 lumen/watt, so I guess the answer would be something like 4000-6000 lumen!
Incandescent Watts...... . ..CFL Watt range... . . ... .. Lumen Range 406075100150 8 - 1013 - 1818 - 2223 - 2834 - 42 450890121017502780
To calculate the resistance of a 5 watt light bulb, you can use the formula P = V^2 / R, where P is power (5 watts) and V is voltage (typically around 120V for a household light bulb). Rearranging the formula to solve for resistance, you get R = V^2 / P. Plugging in the values, R = (120V)^2 / 5W = 2880 ohms. So, a 5 watt light bulb at 120V would have a resistance of 2880 ohms.
In 2 seconds, a 100 Watt light bulb consumes 200 Joules of electrical energy from the electrical supply (100 Watts * 2 seconds = 200 Joules).
A 100-watt electric bulb consumes 200 watt-hours of energy in two hours (100 watts x 2 hours = 200 watt-hours).
If you turn a 60 watt light bulb on and off, it will still consume 60 watts when it is turned on. The act of turning it off does not reduce its power consumption when it is on. However, when the light bulb is turned off, it consumes no power.
To calculate the amperage, you can use Ohm's Law formula: Amperage (A) = Power (W) / Voltage (V). In this case, for a 5 watt bulb at 12 volts, the amperage drawn would be 0.42 amps (5W / 12V = 0.42A).
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
The formula to calculate the energy usage of a light bulb is Power (Watts) x Time (hours) = Energy Used (Watt-hours). For example, a 60-watt light bulb used for 5 hours would consume 300 Watt-hours of energy.
Assuming the batteries have a voltage that matches the bulb's requirement, you would need at least 2 AA batteries connected in series to power a 25-watt bulb. This setup would provide enough voltage and current to light up the bulb.
A 200W light bulb will use 0.2 kWh (kilowatt-hour) of electricity per hour of operation. If the bulb is on for 5 hours, it would consume 1 kWh.
:A: NO the same bulb cannot carry 4 amperes at 15 volts since it Cary 2 amps at 60 volts. It Will significantly dimmer