Wiki User
∙ 12y ago15 litres
Wiki User
∙ 12y agoTo calculate the amount of glucose in the solution, use the formula: mass = volume × concentration
Rearrange the formula to solve for volume: volume = mass / concentration
Substitute the values to find: volume = 75 g / 0.05 = 1500 mL = 1.5 L
Therefore, you would need 1.5 liters of the 5.0% glucose solution to obtain 75 g of glucose.
To obtain a solution that is twenty percent antifreeze, you would add 4 parts water to 1 part antifreeze. This means that for every 1 part of antifreeze, you would add 4 parts of water. This would result in a total of 5 parts of solution, with 1 part being antifreeze and 4 parts being water, achieving a solution that is twenty percent antifreeze.
To achieve a 50% salt solution with 4 liters total volume, the chemist needs 2 liters of each of the 20% and 70% solutions. This is because the resulting solution will be a combination of the two strengths in equal amounts, leading to an overall concentration of 50%.
Organisms other than plants benefit from the production of glucose by autotrophs as they can obtain energy indirectly through the consumption of these autotrophs or other organisms that have consumed autotrophs. Glucose is a universal energy source that fuels various metabolic processes in organisms throughout the food chain.
To make 100g of glucose, you would first need a source of starch, such as corn or potato. You would then hydrolyze the starch using enzymes to break it down into glucose molecules. The resulting glucose solution can be concentrated and purified to obtain the desired 100g quantity.
To obtain its energy.
10 liters.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
10
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
To find the molarity, first calculate the moles of NH3 in 100g of the solution using the mass percent. Then convert the volume of the solution (1 mL) to liters. Finally, divide moles by liters to obtain the molarity.
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
25 gallons
4 litres
Suppose L litres are required.@ 40% it will contain 0.4L of the active ingredient.Then total volume of mixture = L + 100 litresand volume of active ingredient = 0.4L + 25 litresThe strength is (0.4L + 25)/(L + 100) = 30% = 0.3(0.4L + 25) = 0.3*(L + 100)0.4L + 25 = 0.3*L + 300.1L = 5L = 50 litres.
50 gallons @ 3% must be added.
40.8 grams
To determine the amount of 18% solution to add: Let x = volume of 18% solution to be added. 0.18x + 0.10(360) = 0.15(x + 360) Solving for x, you would need to add 75 ml of the 18% solution to the 360 ml of 10% solution to obtain a 15% solution.