By filling in this formula with SI units of the symbols R, T, p, V you'll find the number of moles for ALL possible (ideal) gases according to Ideal Gas Law (Boyle's):
n = p*V / R*T or p*V = n*R*T n= number of moles of any gas => 25 mol (your 'known')p= pressure of (any) gas (Pa) => 1.01325*105 Pa (=1 atm) (Standard)
V= Volume of that gas (m3) => ? (to be calculated)
R= universal Gas constant (J.mol-1.K-1 )=> 8.3145 (universal constant)
T= absolute temperature (K) => 273.15 K (Standard)
With the questioned figures:
V = nRT/p = [25*8.3145*273.15] / [1.01325*105] = 0.56035 (m3) = 560 litres for 25 moles of Ar (or any) gas at (Standard)TP
1,67.1024 argon atoms is equal to 2,773 moles.
8,4 liters of nitrous oxide at STP contain 2,65 moles.
To find the volume of 1.3 moles of 3.42 M NaOH, you can use the formula: Volume = moles / Molarity. In this case, it would be Volume = 1.3 moles / 3.42 M = 0.38 L of NaOH.
To calculate the moles of NaOH in the solution, you first need to convert the volume of the solution from milliliters to liters (65.0 ml = 0.065 L). Then, use the formula moles = molarity x volume in liters to find the moles of NaOH. Plugging in the values, you get moles = 2.20 mol/L x 0.065 L = 0.143 moles of NaOH.
To determine the number of moles of KCl present in a solution, you need to use the formula: moles = molarity x volume (in liters). First, convert the volume from milliliters to liters by dividing by 1000 (50.0 mL = 0.050 L). Then, calculate the moles of KCl by multiplying the molarity (0.552 M) by the volume in liters (0.05 L). This gives you approximately 0.0286 moles of KCl in the solution.
There are 0.25 moles of argon gas present in 5.6 liters at standard conditions (1 mole of any gas occupies 22.4 liters at standard conditions).
1,67.1024 argon atoms is equal to 2,773 moles.
To find the number of moles of argon in 37.9 g, you need to use the molar mass of argon, which is 39.95 g/mol. Divide the given mass by the molar mass to get the number of moles. So, 37.9 g / 39.95 g/mol = 0.95 moles of argon.
At STP, 1 mole of any gas occupies 22.4 L. Therefore, in a 5L sample of argon at STP, there would be 5/22.4 moles of argon, which is approximately 0.223 moles.
55.64
To find the number of moles in 607 g of argon, divide the mass by the molar mass of argon. The molar mass of argon is approximately 40.0 g/mol. So, 607 g รท 40.0 g/mol = 15.175 moles of argon.
There are 0.639 moles in 28.85 grams of Argon. This is calculated by dividing the given mass by the molar mass of Argon which is approximately 39.95 g/mol.
1 mole occupies 22.414 liters So, 1.84 moles will occupy 41.242 liters
To find the number of moles, divide the given mass of argon by its molar mass. The molar mass of argon is approximately 39.95 g/mol. Number of moles of argon = 14.5 g / 39.95 g/mol Number of moles of argon = 0.362 moles
To find the number of moles of argon in 24.7 g, you need to divide the mass of the sample by the molar mass of argon (39.95 g/mol). Therefore, 24.7 g of argon is equal to 0.62 moles (24.7 g รท 39.95 g/mol = 0.62 mol).
To find the number of moles in 15.01 grams of argon, you need to divide the given mass by the molar mass of argon. The molar mass of argon is approximately 39.95 g/mol. So, the number of moles of argon in 15.01 grams would be 15.01 g / 39.95 g/mol = 0.376 moles.
0.125 moles of argon gas contain 7.52 x 10^23 atoms.